Answer:
90000 gallons
Step-by-step explanation:
Given
![Capacity\ at\ 60\% = 540000](https://tex.z-dn.net/?f=Capacity%5C%20at%5C%20%2060%5C%25%20%3D%20540000)
Required
Determine the full capacity
Let the maximum number of gallons be m.
So, we have:
![60\% * m = 54000](https://tex.z-dn.net/?f=60%5C%25%20%2A%20m%20%3D%2054000)
Convert % to decimal
![0.60 * m = 54000](https://tex.z-dn.net/?f=0.60%20%2A%20m%20%3D%2054000)
Divide both sides by 0.60
![m = \frac{54000}{0.60}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B54000%7D%7B0.60%7D)
![m = 90000](https://tex.z-dn.net/?f=m%20%3D%2090000)
<em>Hence, the maximum number of gallons it can hold is 90000 gallons</em>
The two equations would be, respectively, y=12,000-400x and y=6000-300x
Set the two equal to one another and solve for x.
The answer is 60 hours
Answer:
$54
Step-by-step explanation:
300 times 0.06 times 3
0.06 times 3 = 0.18
300 times 0.18 = 54
The simple interest is $54
Answer:
It is a solution
Step-by-step explanation:
y = -4x - 8
Let x = -9 and y = 28
Substitute these values in
28 = -4(-9) -8
28 = 36 -8
28 =28
This is true so it is a solution
![\lim_{x \to \pi /4} \frac{tan x - 1}{x- \pi /4} = \frac{0}{0}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20%20%5Cpi%20%2F4%7D%20%20%5Cfrac%7Btan%20x%20-%201%7D%7Bx-%20%5Cpi%20%2F4%7D%20%20%3D%20%20%5Cfrac%7B0%7D%7B0%7D%20)
With L` Hospital`s Rule ( ( tan x ) ` = 1/ cos^2 x ) :
![\lim_{x \to \pi /4} \frac{1}{cos ^{2} x} = \\ = \frac{1}{cos ^{2} ( \pi /4)} = \\ \frac{1}{1/2}](https://tex.z-dn.net/?f=%20%5Clim_%7Bx%20%5Cto%20%20%5Cpi%20%2F4%7D%20%20%5Cfrac%7B1%7D%7Bcos%20%5E%7B2%7D%20x%7D%20%3D%20%20%5C%5C%20%3D%20%5Cfrac%7B1%7D%7Bcos%20%5E%7B2%7D%20%28%20%5Cpi%20%2F4%29%7D%20%20%3D%20%5C%5C%20%20%5Cfrac%7B1%7D%7B1%2F2%7D%20%20)
=
2