a truck weighs 9,000 pounds. a repair shop sends a tow truck that can pull 5 tons.can the tow truck tow the truck? explain.

1 answer:

4 0

Yes! A ton is 2000 pounds and the tow truck can pull 5 tons, so you multiply 5 by 2000. That is 10,000 pounds and is more than 9,000 pounds which is how much the truck weighs. So the tow truck can tow the truck

Hope this helps

You might be interested in

If x is an even integer greater than 3, then, in terms of

prisoha [69]

Answer:

x^2

Step-by-step explanation:

Any even number raised to two is even.

Eg: 4^2 = 16

12^2 = 144

Etc...

And

Any odd number raised to two is odd.

Eg: 5^2 = 25

13^2 = 169

Etc...

And also x^2 is greater than 2x & x+3 & x+2

6 0

2 years ago

500 is 1/10 as much as 50

Airida [17]

500 is 1/10 as much as 50 [False]

500 is 10 times as much as 50.

6 0

3 years ago

Conti. 7-10 thanks a lot! unhelpful answers will be deleted.

Marysya12 [62]

Answers:

10. b. $\displaystyle 13$

9. b. $\displaystyle 20$

8. a. $\displaystyle 33$

7. a. $\displaystyle 25°$

Step-by-step explanations:

10. Both segments are considered congruent, so turn both expressions into an equation:

$\displaystyle 3x - 5 = x + 7 \hookrightarrow \frac{-12}{-2} = \frac{-2x}{-2} \\ \\ 6 = x$

Plug this back into the equation to get $\displaystyle 13$ on both sides.

9. All edges in a square obtain congruent right angles and edges, so set $\displaystyle 45$ equivalent to the given expression:

$\displaystyle 45 = 2x + 5 \hookrightarrow \frac{40}{2} = \frac{2x}{2} \\ \\ \boxed{20 = x}$

8. Both angles are considered supplementary, so turn both expressions into an equation and set it to one hundred eighty degrees:

$\displaystyle 180 = (4x - 15)° + (x + 30)° \hookrightarrow 180° = (15 + 5x)° \hookrightarrow \frac{165}{5} = \frac{5x}{5} \\ \\ \boxed{33 = x}$

7. In this rectangle, segment EO is a segment bisectour, making these angles Complementary Angles. Therefore, set an equation up to find its complement:

$\displaystyle 90° = 65° + m\angle{VOE} \\ \\ \boxed{25° = m\angle{VOE}}$