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bonufazy [111]
3 years ago
6

Help please ❤️

Mathematics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

yes

Step-by-step explanation:

if u don't touch that money for a long time u will have more money than in the other. hope this helps.

can I please have brainliest.

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10) Jackson’s scores on the first four algebra quizzes are 79, 88, 95, and 71. What score must he earn on the fifth quiz to earn
Hoochie [10]
Based on the given information, let x represent the grade for the fifth quiz.

(79+88+95+71+x)/5=85
(333+x)/5=85
333+x=425
x=92

Jackson would have to earn a 92 on his fifth quiz to earn an average of 85.
5 0
3 years ago
Prove that x-1 is a factor of x^n-1 for any positive integer n.
PolarNik [594]

Answer:    

x-1 is a factor of x^n - 1

Step-by-step explanation:

x-1 is a factor of x^n - 1

We will prove this with the help of principal of mathematical induction.

For n = 1, x-1 is a factor x-1, which is true.

Let the given statement be true for n = k that is x-1 is a factor of x^k - 1.

Thus, x^k - 1 can be written equal to  y(x-1), where y is an integer.

Now, we will prove that the given statement is true for n = k+1

x^{k+1} - 1\\=(x-1)x^k + x^k - 1\\=(x-1)x^k + y(x-1)\\(x-1)(x^k + y)

Thus, x^k - 1 is divisible by x-1.

Hence, by principle of mathematical induction, the given statement is true for all natural numbers,n.

3 0
3 years ago
I just want to know how do you solve these? An example is fine.
Damm [24]
The value is given in question.... put the corresponding value in the equation in place of "x" and you will obtain the value of "y"
4 0
3 years ago
If you calculate the ratio s/r (arc length/radius) for any circle, what does it equal?
Jobisdone [24]

Answer:

central angle, in radians

Step-by-step explanation:

The ratio s/r is equal to the central angle, which must be in radians.

3 0
3 years ago
Prove that sin20 sin40 sin60 sin80=3/16
sineoko [7]
<span> sin20 * sin40 * sin60 * sin80

since sin 60 = </span><span> √3/2

</span>√3/<span>2 (sin 20 * sin 40 * sin 80)
</span>√3/<span>2 (sin 20) [sin 40 * sin 80]
</span>
Using identity: <span>sin A sin B = (1/2) [ cos(A - B) - cos(A + B) ]

</span>√3/<span>2 (sin 20)  (1 / 2) [cos 40 - cos 120]
</span>√3/4<span> (sin 20) [cos 40 + cos 60]
</span>
Since cos 60 = 1/2:

√3/4<span> (sin 20) [cos 40 + (1/2)]
</span>√3/4 (sin 20)(cos 40) + √3/8<span> (sin 20)
</span>
Using identity: <span> sin A cos B = 1/2 [ sin(A + B) + sin(A - B) ]

</span>√<span>3/4 (1 / 2) [sin 60 + sin (-20)] + </span>√3/8<span> (sin 20)
</span>
Since sin 60 = √3/<span>2

</span>√3/8 [√3/2 - sin 20] + √3/8 (sin 20)
3/16 - √3/8 sin 20 + √3/8<span> sin 20
</span>
Cancelling out the 2 terms:
3/16

Therefore,  sin20 * sin40 * sin60 * <span>sin80 = 3/16</span>

6 0
3 years ago
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