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drek231 [11]
3 years ago
9

11

Mathematics
2 answers:
barxatty [35]3 years ago
6 0
No, because the lasts line of the work is not true. 5 and 11 are not equal.
babunello [35]3 years ago
4 0

Answer:

its D 0w0

Step-by-step explanation:

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A package contains 4 red, 2 green, 8 purple, and 6 blue jelly beans. What is the probability of choosing a purple jelly bean, ea
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2/6 i think

Step-by-step explanation:

4 0
4 years ago
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NEED HELP WHAT ARE THSES TWOO!!
lozanna [386]
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8 0
3 years ago
Vector u has its initial point at (17, 5) and its terminal point at (9, -12). Vector v has its initial point at (12, 4) and its
Ratling [72]

\bf \vec{u}~~ \begin{cases} (17,5)\\ (9,12) \end{cases}\implies \implies \stackrel{\textit{component form}}{} \\\\\\ \vec{v}~~ \begin{cases} (12,4)\\ (3,-2) \end{cases}\implies \implies \stackrel{\textit{component form}}{} \\\\[-0.35em] ~\dotfill

\bf 3\vec{u}\implies 3\implies  \\\\\\ 2\vec{v}\implies 2\implies  \\\\\\ 3\vec{u}-2\vec{v}\implies -\implies + \\\\\\ \implies  \\\\[-0.35em] ~\dotfill\\\\ ||3\vec{u}-2\vec{v}||\implies ||||\implies \sqrt{(-16)^2+33^2} \\\\\\ \sqrt{1345}\implies 36.67

3 0
3 years ago
I need help on these 2 questions pls.
Varvara68 [4.7K]
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5 0
3 years ago
With a detailed explanation from the internet<br> 1/(x-5)+3/(x+2)=4
irga5000 [103]

Answer:

\boxed{ \sf x=\dfrac{4\pm\sqrt{43}}{2}}

Explanation:

\rightarrow \sf \dfrac{1}{x-5}+\dfrac{3}{x+2}=4

<u>make the denominators same</u>

\rightarrow \sf \dfrac{1(x+2)}{(x-5)(x+2)}+\dfrac{3(x-5)}{(x+2)(x-5)}=4

<u>join the fractions together</u>

\rightarrow \sf \dfrac{x+2+3x-15}{(x-5)(x+2)}=4

<u>cross multiply</u>

\rightarrow \sf x+2+3x-15=4(x-5)(x+2)

<u>simplify</u>

\rightarrow \sf 4x-13=4x^2-12x-40

<u>group the variables</u>

\rightarrow \sf 4x^2-16x-27 = 0

<u>use quadratic formula</u>

\rightarrow \sf x = \dfrac{-\left(-16\right)\pm \sqrt{\left(-16\right)^2-4\cdot \:4\left(-27\right)}}{2\cdot \:4}

<u>simplify the following</u>

\rightarrow \sf x=\dfrac{4\pm\sqrt{43}}{2}

7 0
2 years ago
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