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labwork [276]
3 years ago
15

What is the ratio of 2 cups of flour and 1 cup of milk.

Mathematics
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

either 1:2 or 2:1. I think.

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PLEASE HELP ASAP! I need the answer for this question anyone ?
Alexxandr [17]

Answer:

A: sqrt(11)

B: 4.2

C: sqrt(26)

Step-by-step explanation:

First, 4^2 = 16

That means that sqrt 11 is smaller than 4.2 (a value greater than 4). This is because sqrt16>sqrt11.

Sqrt(26) is greater than sqrt(25) = 5. That means that it's greater than 4.2.

Hence, the order given above.

6 0
3 years ago
What is the answer? #16 . thanks
rjkz [21]
If I got it correctly, the question is what is  24x^2y^6-16x^6y^2+4xy^2 divided by 4xy^2 and the answer is 6xy^4-4x^5+1.

6 0
3 years ago
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AysviL [449]
Wow! So so so cool lol
8 0
3 years ago
Read 2 more answers
82. Subtract 12x? + 6y - 3 and 3x? - 9y + 12
balu736 [363]

Answer:

-x^2+15y-15

Answer if it is a ^2

Step-by-step explanation:

2x^2 + 6y - 3 -(3x^2 - 9y + 12)=

2x^2+6y-3-3x^2+9y-12=

-x^2+15y-15

is it a ^2 or a question mark

3 0
3 years ago
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first the
Svetlanka [38]

Answer:

The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.

Step-by-step explanation:

Given:

A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.

The tax of the first city was 6% and the tax of the second city was 10%.

Total hotel tax paid for two cities with $670.

Now, to find the hotel charge in each city before tax.

Let the hotel charge in first city before tax be x.

And the hotel charge in second city before tax be y.

<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>

<em>Thus</em>,

y=x-1500   ........(1)

<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>

6% of x + 10% of y = $670.

\frac{6x}{100} +\frac{10y}{100} =670

0.06x+0.10y=670

Substituting the value of y from equation (1) we get:

0.06x+0.10(x-1500)=670

0.06x+0.10x-150=670

0.16x-150=670

<em>Adding both sides by 150 we get:</em>

0.16x=820

<em>Dividing both sides by 0.16 we get:</em>

x=5125.

<em>The hotel charge in first city before tax = $5125.</em>

Now, substituting the value of x in equation (1) we get:

y=x-1500

y=5125-1500

y=3625.

<em>The hotel charge in second city before tax = $3625.</em>

Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.

5 0
4 years ago
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