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2 years ago

Kendra has $50 to spend on mittens. she wants to buy as many as possible. If each pair cost $3 how much can see buy?

Mathematics

2 answers:

nydimaria [60]2 years ago

7 0

Answer:

16 pairs of mittens

Step-by-step explanation:

16 x 3 is 48

Verizon [17]2 years ago

4 0

Solution:

Note that:

1 pair of mittens = $3
Kendra = $50

We already know:

The closest number to 50 and is divisible by 3 is 48.

=> x pair of mittens = $3x = 48

=> $3x = 48

=> x = 48/3

=> x = 16

Kendra can buy 16 mittens.

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50+ POINTS I NEED HELP

olga nikolaevna [1]

Answer:

21 yard line

Step-by-step explanation:

Ok we start out on the 20 yard line, we need to add the yards together.

We add the 6 to the 20:

20+6=26

Then we subtract the 8 yards from our new 26:

26-8=18

Then we add the 18 by 3:

18+3=21

Therefore,

The Answer is 21 Yard Line.

Hope I could help, If you need some more assistance ask me!

8 0

3 years ago

Tickets for seniors prom cost $25 for individual tickets and $40 for couples tickets. They collected a total of 2500 from ticket

quester [9]

Answer: 20

Step-by-step explanation:

Given

The cost of an individual ticket is $25

The cost of a couple's ticket is $40

The total sale is $2500

total ticket sold is 70

Suppose there are x individuals and y couples

$\therefore x+y=70\quad \ldots(i)\\\\25x+40y=2500\quad \ldots(ii)\\\text{Solving }(i)\ \text{and}\ (ii)\ \text{we get}$

$x=20,y=50$

So, they sold 20 tickets of the individual.

8 0

3 years ago

If you help me I'll make as brilliant

MissTica

The answer is A) 3/100.

5 0

2 years ago

Read 2 more answers

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

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2 years ago

A rectangle has a perimeter of 116 centimeters and a length of 26 centimeters. What is the width of the rectangle?

Andre45 [30]

26+26=52 which is the side lengths.
116-52=64 which is the other side lengths together. So one side length 32. 32+32+26+26=116

8 0

3 years ago

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