Calculater I'm pretty sure
There is no horizontal asymptote.
Angles XQL and MQR are congruent because they are vertical angles. So
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
Solve for <em>b</em> :
209 - 13 <em>b</em> = 146 - 4 <em>b</em>
209 - 146 = 13 <em>b</em> - 4<em> b</em>
63 = 9 <em>b</em>
<em>b</em> = 63/9 = 7
Then the measure of angle XQL is
(209 - 13*7)º = 118º
(X-5)2+3(X-5)+9 = 0
let expand the equation
(x)x2-(5)x2 + 3(x)-3(5) + 9 = 0
2x-10+3x-15+9=0
collect like terms
2x+3x-10-15+9 =0
5x-10-6 =0
5x-16=0
5x=0+16
5x=16
divide both side by 5 we have
x=16/5
The smaller the length u can figure out and if u can't put a small square in the cornorn
