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Ray Of Light [21]

3 years ago

11

A bus eats 4 people in a row and there are 12 rows how would fit on 2 buses?

1 answer:

BARSIC [14]3 years ago

6 0

Answer:

$4 \times 12 \times 2 = 96$

96 people in total.

BTW its seats and I think you meant "how many"

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Answer two questions about systems A and B

Lunna [17]

Step-by-step explanation:

I dont see any questions

Can you send a picture to see if I can help

7 0

2 years ago

Read 2 more answers

4. Find the distance between the two points. Round to the nearest tenth if necessary.

Archy [21]

Answer:

Distance = 7.8 units

Step-by-step explanation:

In coordinate geometry, the distance between the 2 points is given by

$Distance = \sqrt{(x1-x2)^{2} + (y1-y2)^{2} }$

where (x1,y1) and (x2,y2) are coordinates of the 2 points.

Above the 2 points given are, (-2,-1) and (3,5).

<em>x1 = -2 , y1 = -1 , x2 = 3, y2 = 5</em>

<em> $Distance = \sqrt{((-2)-(3))^{2} + ((-1)-(5))^{2} }$ </em>

<em> $Distance = \sqrt{61}$ </em>

<em>Distance = 7.8102 units</em>

To the nearest tenth, Distance = 7.8 units

3 0

3 years ago

The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi

storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

$V = \frac{1}{3}\pi r^{2}h$

Differentiate the equation with respect to time t, such that

$\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)$

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)$

To differentiate the product,

Let r² = u, so that

$\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)$

Then, using product rule

$\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]$

Since $u = r^{2}$

Then, $\frac{du}{dr} = 2r$

Using the Chain's rule

$\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}$

∴ $\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]$

Then,

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

Now,

From the question

$\frac{dr}{dt} = 7 m/min$

$\frac{dV}{dt} = 236 m^{3}/min$

At the instant when $r = 99 m$

and $V = 180 m^{3}$

We will determine the value of h, using

$V = \frac{1}{3}\pi r^{2}h$

$180 = \frac{1}{3}\pi (99)^{2}h$

$180 \times 3 = 9801\pi h$

$h =\frac{540}{9801\pi }$

$h =\frac{20}{363\pi }$

Now, Putting the parameters into the equation

$\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]$

$236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]$

$236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]$

$708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}$

$708 = 30790.75 \frac{dh}{dt} + 76.36$

$708 - 76.36 = 30790.75\frac{dh}{dt}$

$631.64 = 30790.75\frac{dh}{dt}$

$\frac{dh}{dt}= \frac{631.64}{30790.75}$

$\frac{dh}{dt} = 0.021 m/min$

Hence, the rate of change of the height is 0.021 meters per minute.

3 0

2 years ago

There's a plane that flies at an altitude of 25,000 feet. There's a submarine that dives to a depth of 600 feet below sea level.

ella [17]

25,000 + 600 considering they would meet at 0, so they are 25,600 feet apart

8 0

3 years ago

State the gradient of the line perpendicular to the line y=3x-2

kherson [118]

Answer:

-1/3

Step-by-step explanation:

3 is the gradient of the other line

m1×m2=-1 (equation for perpendicular lines)

m1×3= -1

m1= -1/3

Pls confirm if its correct

correct me if wrong

thanks! :)

7 0

2 years ago