Note that when x=0, y=-6, so d cannot be right. Note that 2 and -1.5 are solutions. The only answer choice that has both as zeroes is a.
Answer:
i don't know maybe D. 2 and 3
Given:
The table of values is
Number of Students : 7 14 21 28
Number of Textbooks : 35 70 105 140
To find:
The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.
Solution:
The ratio of number of textbooks to number of students are
![\dfrac{35}{7}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B35%7D%7B7%7D%3D5)
![\dfrac{70}{14}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B70%7D%7B14%7D%3D5)
![\dfrac{105}{21}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B105%7D%7B21%7D%3D5)
![\dfrac{140}{28}=5](https://tex.z-dn.net/?f=%5Cdfrac%7B140%7D%7B28%7D%3D5)
All the ratios of the two quantities are proportional and equivalent to the unit rate.
Let y be the number of textbooks and x be the number of students, then
![\dfrac{y}{x}=k](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3Dk)
Here, k=5.
![\dfrac{y}{x}=5](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3D5)
![y=5x](https://tex.z-dn.net/?f=y%3D5x)
Hence the rate of change is constant that is 5.
Answer:
10 cm³
Step-by-step explanation:
The equation for density is: d = m/v, where d is the density, m is the mass, and v is the volume.
Here, d = 2.5 and m = 25.0, so plug these into the equation to solve for v:
d = m/v
2.5 = 25/v
Multiply both sides by v:
2.5v = 25
Divide by 2.5:
v = 25/2.5 = 10
Thus, the volume is 10 cm³.