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2 years ago

What is the area of the given figure in square centimeters? 15 3/4 21 3/8 27 39 3/8

Mathematics

2 answers:

kobusy [5.1K]2 years ago

8 0

Answer:

21 /3/8 cm^2.

Step-by-step explanation:

Area = area of rectangle + area of the triangle

= 3 1/2 * 4 1/2 + 1/2 * 4 1/2 * 2 1/2

= 7/2 * 9/2 + 1/2 * 9/2 * 5/2

= 63/4 + 45/8

= 126/8 + 45/8

= 171/8

= 21 /3/8 cm^2.

bulgar [2K]2 years ago

7 0

Answer: 21.375 cm2

Step-by-step explanation:

Area of rectangle = length x width = 3.5 x 4.4 = 15.75 cm2

Area of triangle = 1/2 x base x height = 1/2 x 2.5 x 4.5 = 5.625 cm2

Add rectangle and triangle area = 21.375 cm2

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If Joseph buys a T.V. At 35% off and it’s original costs $599.99 how much did he pay for the tv?

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3 years ago

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Answer:

The answer is $x=-16$ ± $2\sqrt{3}$ in exact form or $x=-12.535898$ , $x=-19.464102$ in decimal form.

Step-by-step explanation:

To solve this problem, start by moving all terms to the left side of the equation and simplify. Simplify the equation by subtracting 12 from both sides of the equation and squaring $x+16$ , which will look like $x^{2} +32x+256-12=0$ . Next, simplify the equation again, which will look like $x^{2} +32x+244=0$ .

Then, use the quadratic formula to find the solutions. The quadratic formula looks like $\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}$ .

For this problem, the quadratic variables are as follows:

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$c=244$

The next step is to substitute the values $a=1$ , $b=32$ , and $c=244$ into the quadratic formula and solve. The quadratic formula will look like $\frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}$ . To simplify the equation, start by simplifying the numerator, which will look like $x=\frac{-32(+-)4\sqrt{3} }{2*1}$ . Then, multiply 2 by 1 and simplify the equation, which will look like $x=-16(+-)2\sqrt{3}$ . The final answer is $x=-16$ ± $2\sqrt{3}$ in exact form. In decimal form, the final answer is $x=-12.535898$ , $x=-19.464102$ .

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