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ololo11 [35]
3 years ago
7

Explain how to find the gcf of three numbers

Mathematics
1 answer:
Tasya [4]3 years ago
5 0
The gcf of numbers is the greatest common factor of the numbers, i.e. the greatest number which divides the numbers without a remainder.
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What is the product of (-a+3)(a+4)
4vir4ik [10]

Answer:-a^2-a+12

Step-by-step explanation:

(-a+3)(a+4)

Clear brackets

-a^2-4a+3a+12

Add like terms

-a^2-a+12

4 0
3 years ago
I really need help with this!!! someone help please
Minchanka [31]

Answer:

156 in squared

Step-by-step explanation:

So the formulas will be stated below

Parallelogram Area= 1/2h(b1+b2)

Square Area= Bh

So first do

(4)(12+6)

(4)(18)

No need to half it bc there's the same shape at the bottom

72+18+30+36

6(3)

3x5(2)

12(3)

5 0
3 years ago
A line parallel to a triangle's side splits AB into lengths of x - 7 and x - 3. The other side, AC, is split into lengths of x a
Nesterboy [21]

Answer:

Step-by-step explanation:

6 0
4 years ago
An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on
butalik [34]

Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a>0, the minimum value of the function will happen for x = x_v

C(x)=x²-180x+20,482

This means that a = 1, b = -180, c = 20482

How many engines must be made to minimize the unit cost?

x value of the vertex. So

x_{v} = -\frac{b}{2a} = -\frac{-180}{2(1)} = 90

90 engines must be made to minimize the unit cost.

3 0
3 years ago
Let g(x) = 2x and h(x) = x^2 + 4. Find the value.(g o h) (0)a) 4b) 8c) 0d) 16
Paul [167]
\begin{gathered} \text{Given} \\ g(x)=2x \\ h(x)=x^2+4 \end{gathered}

Solve for (g o h)(x)

\begin{gathered} (g\circ f)(x)=g\big(f(x)\big) \\ (g\circ f)(x)=g(x^2+4) \\ (g\circ f)(x)=2(x^2+4) \\ (g\circ f)(x)=2x^2+8 \end{gathered}

Next substitute x = 0

\begin{gathered} (g\circ f)(x)=2x^2+8 \\ (g\circ f)(0)=2(0)^2+8 \\ (g\circ f)(0)=8 \end{gathered}\text{Therefore, }(g\circ f)(0)=8

5 0
2 years ago
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