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drek231 [11]
3 years ago
7

Write 10^3 as a multiplication expression having repeated factors?

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0

Answer:

{10}^{3}  \\ 10 \times 10 \times 10

mezya [45]3 years ago
4 0
10x10x10
the power of 3 makes the 10 multiples by itself 3 times. 10x10 being 100, and 100x10 being 1000!
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Sung loo worked 54 hours during a special sale at the store. 10 hours was time and a half, and 4 hours were at double time. Her
DanielleElmas [232]

Answer:

$432.18

Step-by-step explanation:

Time and a half = 50% more pay rate / 1.5*6.86 = $10.29 per hour

Double time = 2*6.86 = $13.72 per hour

Rest of the time => At regular rate

Total Amount = 10(10.29) + 4(13.72) + (54 - 10 - 4)(6.86)

                       = 10(10.29) + 4(13.72) + (40)(6.86)

                       = $ 432.18

6 0
3 years ago
Read 2 more answers
Solve for x y=c(x+b)
sergeinik [125]

Step-by-step explanation: To solve for x in this literal equation, I would first distribute the C through the parentheses to get y = cx + cb.

Now subtract cb from both sides to get y - cb = cx.

Finally, divide both sides by c to get y - cb / c = x.

5 0
3 years ago
Find the<br>simple interest:<br>Princpd $6000<br>Interest Rate 5%<br>Time: 6 months<br>Start​
sattari [20]

Answer: The interest is: $150.00

The formula we'll use for this is the simple interest formula, or:

Where:

   P is the principal amount, $6000.00.

   r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

   t is the time involved, 6....month(s) time periods.

   Since your interest rate is "per year" and you gave your time interval in "month(s)" we need to convert your time interval into "year" as well.

       Do this by dividing your time, 6- month(s), by 12, since there's 12 months in 1 year.

   So, t is 0.5....year time periods.

To find the simple interest, we multiply 6000 × 0.05 × 0.5 to get that:

The interest is: $150.00

8 0
3 years ago
What is the length of the arc on a circle with radius 20 in. intercepted by a 15° angle? Use 3.14 for π . Round the answer to th
Fofino [41]
We know, length of arc = Ф/360 * 2πr
= 15/360 * (2 * 3.14 * 20)
= 1/24 * (125.6)
= 5.23

In short, Your Answer would be 5.23 Inches

Hope this helps!
5 0
3 years ago
15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find<br>dy/dx at =22/7*4<br>​
Sav [38]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}

It looks like we're given

\begin{cases}x=a\sin(2t)(1+\cos(2t))\\y=b\cos(2t)(1-\cos(2t))\end{cases}

where <em>a</em> and <em>b</em> are presumably constant.

Recall that

\cos^2t=\dfrac{1+\cos(2t)}2

\sin^2t=\dfrac{1-\cos(2t)}2

so that

\begin{cases}x=2a\sin(2t)\cos^2t\\y=2b\cos(2t)\sin^2t\end{cases}

Then we have

\dfrac{\mathrm dx}{\mathrm dt}=4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t

\dfrac{\mathrm dy}{\mathrm dt}=-4b\sin(2t)\sin^2t+4b\cos(2t)\sin t\cos t

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{4b\cos(2t)\sin t\cos t-4b\sin(2t)\sin^2}{4a\cos(2t)\cos^2t-4a\sin(2t)\cos t\sin t}

\implies\boxed{\dfrac{\mathrm dy}{\mathrm dx}=\dfrac ba\tan t}

where the last reduction follows from dividing through everything by \cos(2t)\cos^2t and simplifying.

I'm not sure at which point you're supposed to evaluate the derivative (22/7*4, as in 88/7? or something else?), so I'll leave that to you.

8 0
3 years ago
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