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3 years ago

5

Can someone please help me? I just need to get the variable alone to see what it equals, if it doesn’t have a solution, or if it

can be any number. Show your work if possible :P
13-3p = -5(3+2p)

Fank chus

2 answers:

love history [14]3 years ago

4 0

Answer:

the answer would be p= -4

13-3p = -5(3+2p)

13-3p = -15-10p

13 = -15-7p

28 = -7p

p = -4

Gennadij [26K]3 years ago

4 0

P=4 i think i'm not sure

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There were 900 students enrolled in a high school in 2009 and 1,500 students enrolled in the same high school in 2012. The stude

Volgvan

Answer:

(A)

$(t_0,P_0)=(0,900)$

$(t_1,P_1)=(3,1500)$

(B)

$m=200$

(C)

$P=200t+900$

(D)

The high school's enrollment in 2017 is 2500

Step-by-step explanation:

Let's assume time starts since 2009

so, In 2009 , t=0

P=900

In 2012,

t=2012-2009=3

P=1500

(A)

So, we have points as

$(t_0,P_0)=(0,900)$

$(t_1,P_1)=(3,1500)$

(B)

we can use slope formula

$m=\frac{P_2-P_2}{t_2-t_1}$

we can plug values

$m=\frac{1500-900}{3-0}$

$m=200$

we know that

slope is rate of change of P with respect to time

so, slope means increase in population is 200 per year

(C)

we can use point slope form of line

$y-y_1=m(x-x_1)$

$m=200$

$(t_0,P_0)=(0,900)$

$P-900=200(t-0)$

$P=200t+900$

(D)

In 2017 ,

t=2017-2009=8

we can plug t=8

and we get

$P=200(8)+900$

$P=2500$

The high school's enrollment in 2017 is 2500

4 0

3 years ago

How do I solve this problem? You drive your car on a cold day (20^oF Outside) the engine overheats to about (220^oF). When you p

GaryK [48]

$ln(T- \frac{20}{200})=-0.11t \\ e^{ln(T- \frac{20}{200})}=e^{-0.11t} \\ T- \frac{20}{200} =e^{-0.11t} \\ T-0.1=e^{-0.11t} \\ T=e^{-0.11t}+0.1$
Then, now that we have solved for T, we can evaluate and solve for t=20 minutes.
$T=e^{-0.11t}+0.1 \\ T=e^{-0.11*20}+0.1 \\ T=e^{-2.2}+0.1 \\ T=0.11+0.1 \\ T=0.21$

7 0

3 years ago

What is the step for 6b+8=-4

VMariaS [17]

Answer

Step-by-step explanation:

6b+8=-4

subtract 8 from both sides

6b=-4-8

solve -4-8

and get, 6b=-12

divid by 6

b=-2

7 0

3 years ago

Abigail and Bailey wash dogs to make extra money. Abigail can wash all of the dogs in 5 hours. Bailey can wash all the dogs in 3

aleksandr82 [10.1K]

Answer: The correct option is (b) $1\dfrac{7}{8}~\textup{hours}.$

Step-by-step explanation: Given that Abigail and Bailey wash dogs to make extra money. Abigail can wash all of the dogs in 5 hours and Bailey can wash all the dogs in 3 hours.

We are to find the time taken by them if they wash the dogs together.

Abigail can wash the dogs in 5 hours.

So, in 1 hour, the fraction of the dogs Abigail can wash is given by

$\dfrac{1}{5}.$

Bailey can wash the dogs in 3 hours.

So, in 1 hour, the fraction of the dogs Bailey can wash is given by

$\dfrac{1}{3}.$

Hence, if they work together, then the fraction of the dogs that they wash in 1 hour is given by

$\dfrac{1}{5}+\dfrac{1}{3}=\dfrac{3+5}{15}=\dfrac{8}{15}.$

Therefore, the time taken by them to wash the dogs if they work together will be

$t=\dfrac{1}{\frac{8}{15}}=\dfrac{15}{8}=1\dfrac{7}{8}~\textup{hours}.$

Thus, option (b) is correct.

7 0

3 years ago

un tráiler a recorrido 180 km consumiendo 12 litros de gasolina si el recorrido Total que debe hacer son 540 km ¿Cuánta gasolina

ss7ja [257]

Answer:

Necesitara 36 litros de gasolina para recorrer 540 km

Step-by-step explanation:

K G

180 12

540 X

=(540x12)/180

=6480/180

=540

4 0

3 years ago