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kipiarov [429]
3 years ago
14

Which of the following events are disjoint? A) Choose a student at random from a statistics class. Event A is that the student i

s a junior. Event B is that the student is a senior. B.Choose a student at random from a statistics class. Event A is that the student is a psychology major. Event B is that the student is a statistics major. C.Choose a student at random from a statistics class. Event A is that the student is at least 5'8\" tall. Event B is that the student weighs at least 160 pounds.
Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0
The answer would be : A.) event A  is that the student is a junior. Event B is that the student is a senior
Disjoints refer to a condition Where the events cant be interlace with each other, no one from event A is exist in Event B. The member of junior year COULDN'T  be a member of senior year and vice versa

hope this helps


g100num [7]3 years ago
5 0
"Choose a student at random from a statistics class. Event A is that the student is a junior. Event B is <span>that the student is a senior" is the event that is disjoint. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you. </span>
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Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
The following picture is a square pyramid where DE=8 cm and m∠ADE=60°.
Goryan [66]

<u>Given</u>:

The length of DE is 8 cm and the measure of ∠ADE is 60°.

We need to determine the surface area of the pyramid.

<u>Length of AD:</u>

The length of AD is given by

cos 60^{\circ}=\frac{FD}{8}

       4=FD

Length of AD = 8 cm

<u>Slant height:</u>

The slant height EF can be determined using the trigonometric ratio.

Thus, we have;

     sin \ 60^{\circ}=\frac{EF}{8}

sin \ 60^{\circ} \times 8=EF

      \frac{\sqrt{3}}{2} \times 8=EF

          4\sqrt{3}=EF

Thus, the slant height EF is 4√3

<u>Surface area of the square pyramid:</u>

The surface area of the square pyramid can be determined using the formula,

SA=Area \ of \ square + \frac{1}{2} (Perimeter \ of \ base ) (slant \ height)

Substituting the values, we have;

SA=8^2+\frac{1}{2}(8+8+8+8)(4 \sqrt{3})

SA=64+\frac{1}{2}(32)(4 \sqrt{3})

SA=64+(16)(4 \sqrt{3})

SA=64+64 \sqrt{3}

The exact form of the area of the square pyramid is 64+64 \sqrt{3}

Substituting √3 = 1.732 in the above expression, we have;

SA = 64 + 110.848

SA = 174.848

Rounding off to one decimal place, we get;

SA = 174.8

Thus, the area of the square pyramid is 174.8 cm²

7 0
3 years ago
Read 2 more answers
2 + 10 = 24<br>3 + 6 = 27<br>7 + 2 = 63<br>5 + 3 = ????​
True [87]
  • Answer:

<em>40</em>

  • Step-by-step explanation:

<em>2 + 10 = 24</em>

<em>2(2 + 10) = 2×12 = 24</em>

<em>3 + 6 = 27</em>

<em>3(3 + 6) = 3×9 = 27</em>

<em>7 + 2 = 63</em>

<em>7(7 + 2) = 7×9 = 63</em>

<em>5 + 3 = 40</em>

<em>5(5 + 3) = 5×8 = 40</em>

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3 years ago
How to solve this problem
PolarNik [594]
X- 6/4=7
x-6=7×4
x-6=28
x=28-6
x=22
4 0
3 years ago
John wants to find the center of a wall so he can hang a picture. He measures the wall and determines it is 65.25" wide. 65.25"
Viktor [21]

It is given that John wants to find the center of a wall so he can hang a picture. So, John measures the wall and <u>determines</u> it is 65.25 inches wide. Since John has determined that the wall measures a particular amount that means that John has <u>quantified</u> the width of the wall, which in this case comes out to be 65.25 inches.

Again, this is a single number. This means that the width of the wall is a <u>discrete</u> quantity.

Thus, 65.25 inches or 65.25" is a Quantitative and Discrete type of data. Thus, out of the given options, the first option is the correct one.

6 0
3 years ago
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