<span>An obtuse triangle will have one and only one obtuse angle. </span>
<span>The other two angles are acute angles.</span>
<span>The sum of the two angles other than the obtuse angle is less than 90º.<span /></span>
<span><span>The side opposite to the obtuse angle is the longest side of the triangle.</span></span>
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</span><span>The points of concurrency, the Circumcenter and the Orthocenter lie outside of an obtuse triangle, while Centroid and Incenter lie inside the triangle.
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The measure of the third angle would be 159 degrees
Answer:
NM > LN
Step-by-step explanation:
Here, we want to write an inequality
we should beat it in mind that, the greater the angle that a side of a triangle faces, the greater its length will be relatively
as we can see, the side NM faces the greater angle of 83, relative to the side LN that faces the angle of 56;
So we can conclude that;
NM > LN
Answer:
807.8 in^2
Step-by-step explanation:
The total area of the box is the sum of the areas of all faces of the box. The top, bottom, front, and back faces are rectangles 18 in long. The end faces each consist of a rectangle and a triangle. We can compute the sum of these like this:
The areas of top, bottom, front, and back add up to be 18 inches wide by the length that is the perimeter of the end: 2·5in +2·8 in + 9.6 in = 35.8 in. That lateral area is ...
(18 in)(35.6 in) = 640.8 in^2
The area of the triangle on each end is equivalent to the area of a rectangle half as high, so we can compute the area of each end as ...
(9.6 in)(8.7 in) = 83.52 in^2
Then the total area is the lateral area plus the area of the two ends:
640.8 in^2 + 2·83.52 in^2 = 807.84 in^2 ≈ 807.8 in^2
