Answer:
t > 1380
Step-by-step explanation:
Subtract 7200 from both sides
10t + 7200 - 7200 > 21000 - 7200
Simplify
10t > 13800
Divide both sides by 10
10t/10 > 13800/10
Simplify
t > 1380
Answer:
D) 2p+14/p
Step-by-step explanation:
Answer:
55.734 mph
Step-by-step explanation:
Let's call the wind speed x and the time of flight t.
Then, we can write the following equation, knowing that the distance is equal speed times time of flight:
910 = (350+x) * t
660 = (350-x) * t
If we isolate t in both equations and compare its value, we have that:
910 / (350+x) = 660 / (350-x)
(350+x)/(350-x) = 910/660
350 + x = 1.3788 * (350-x)
350 + x = 482.58 - 1.3788x
2.3788x = 132.58
x = 55.734 mph
Answer:
13
Step-by-step explanation:
Since OCB forms a right triangle, you can find the length of side OB and therefore the radius by simply using the pythagorean theorem. The first step is to note that, since AB=24 and OC bisects that, that both CB and AC have length 12. Therefore, the radius is
. Hope this helps!
Answer:
Two imaginary solutions:
x₁= 
x₂ = 
Step-by-step explanation:
When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.
The discriminant gives us information on how the solutions of the equations will be.
- <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
- <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
- <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)
So now we will work with the equation given: 4x - 3x² = 10
First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0
So:
4x - 3x² = 10
-3x² + 4x - 10 = 0 will be our equation
with this information we have that a = -3 b = 4 c = -10
And we will find the discriminant: 
Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>
To proceed to solve the equation we will use the general formula
x₁= (-b+√b²-4ac)/2a
so x₁ = 
The second solution x₂ = (-b-√b²-4ac)/2a
so x₂=
These are our two solutions in the imaginary numbers.