The solutions to the system of equations are (-2,-6) and (4,6)
<h3>How to determine the system of equations?</h3>
We have:
-2x + y = -2

Next, we plot the graph of both functions.
From the attached graph, the equations intersect at (-2,-6) and (4,6)
Hence, the solutions to the system of equations are (-2,-6) and (4,6)
Read more about system of equations at:
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Answer:
x =0,1,2,3,4,5,6
P(x) =0,4,8,12,16,20,24
Step-by-step explanation:
P(x)= 4x
4 x 1 = 4
4 x 2 = 8
4 x 3 =12
4 x 4 = 16
4 x 5 = 20
4 x 6 = 24
No 12.14 is not bigger than 12.44
12.14 < 12.44
Answer:β=√10 or 3.16 (rounded to 2 decimal places)
Step-by-step explanation:
To find the value of β :
- we will differentiate the y(x) equation twice to get a second order differential equation.
- We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β
y(x)=c1cosβx+c2sinβx
we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.
Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate βx in each case and multiply with the differential of c1cosx and c2sinx respectively.
lastly the differential of sinx= cosx and for cosx = -sinx.
Knowing all these we can proceed to solving the problem.
y=c1cosβx+c2sinβx
y'= β×c1×-sinβx+β×c2×cosβx
y'=-c1βsinβx+c2βcosβx
y''=β×-c1β×cosβx + (β×c2β×-sinβx)
y''= -c1β²cosβx -c2β²sinβx
factorize -β²
y''= -β²(c1cosβx +c2sinβx)
y(x)=c1cosβx+c2sinβx
therefore y'' = -β²y
y''+β²y=0
now we compare this with the second order D.E provided in the question
y''+10y=0
this means that β²y=10y
β²=10
B=√10 or 3.16(2 d.p)
Answer:
1) 378.1 in²
2) 8.4 m²
Step-by-step explanation:
Area of sector= 
1) Area of sector

2) Area of sector
