1) 13.111713 What is the decimal place
2 answers:
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Answer:
D
Step-by-step explanation:
<em>The statements are shown below:</em>
<em>A) She used the wrong number as a repeated factor and should have evaluated -2x2x2x2x2x2x2x2. </em>
<em>B) She used the wrong number as a repeated factor and should have evaluated -(8x8). </em>
<em>C) She misinterpreted the exponential form and should have multiplied -2 and 8. </em>
<em>D) She made a sign error when multiplying and should have had 256 as a final answer.</em>
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<u>Solution:</u>
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The problem to simplify is:
Haley's steps are shown below:
Generally,
is actually "a" multiplied "b" times.
So, Haley wrote "-2" eight times multiplied together. That is okay.
Now,
We are dealing with negative numbers.
- When negative numbers are multiplied "odd" number of times, the answer is negative.
- When negative numbers are multiplied "even" number of times, the answer is positive.
Haley wrote "-2" eight times, which is EVEN number of times, so the answer would be POSITIVE. But, Haley's answer is negative. Which is wrong. But "256" is right.
Haley's error is:
Answer choice D
This is a simple 
Pythagorean Theorem problem.
So here we go:
Imagine a right triangle with 2 legs and a hypotenuse.
The Pole is the vertical leg. The Cable is the hypotenuse. The distance on the ground between the cable and the pole is the 3rd leg.
We are trying to find the hypotenuse which is C in our Pythagorean Theorem.
Thus:
Add the squares:
Now take the square root of both sides:
*Remember that in triangles, we cannot have a negative value for the length. (If it's possible, please contact the Nobel Prize admins).
Thus:
So here we go:
Imagine a right triangle with 2 legs and a hypotenuse.
The Pole is the vertical leg. The Cable is the hypotenuse. The distance on the ground between the cable and the pole is the 3rd leg.
We are trying to find the hypotenuse which is C in our Pythagorean Theorem.
Thus:
Add the squares:
Now take the square root of both sides:
*Remember that in triangles, we cannot have a negative value for the length. (If it's possible, please contact the Nobel Prize admins).
Thus: