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shtirl [24]
3 years ago
10

9. Are you given enough information to determine whether the quadrilateral is a parallelogram? Explain.

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

Answer:

C) Yes, if one pair of opposite sides of a quadrilateral are congruent and parallel, then the quadrilateral is a parallelogram

Step-by-step explanation:

Assuming XY is congruent and parallel to WZ, XY and WZ will also be congruent and parallel to each other. Hence these sides form a parallelogram

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Help Help!!!!!!!!!!!!!!!
BabaBlast [244]

Answer:

\frac{7}{10} y

Step-by-step explanation:

To add fractions <em>with the same denominator</em>, simply add the numerators:

\frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}

So:

\frac{3}{10} y+\frac{4}{10} y=\frac{7}{10} y

6 0
3 years ago
Students were asked to choose their favorite sport
r-ruslan [8.4K]

Answer:

5/9-1/9=4/9

Step-by-step explanation:

5/9 chose basketball or soccer. 1/9 chose basketball.

<h3>answer is 4/9</h3>
4 0
3 years ago
Which of the following is an example of simple harmonic motion?
Klio2033 [76]

the answer would be C

5 0
3 years ago
Read 2 more answers
Susie has a bag of marbles containing 3 Red, 7 Green, and 10 Blue marbles.
morpeh [17]

Answer:

1) a) 0.0945

b) 0.1062

2) a) 0.0138

b) 0.00081

3) a) 0.00094

b) 0.00083

4) 301.68 cents

5) 0.0056

Step-by-step explanation:

Since there are 3 Red, 7 Green, and 10 Blue marbles.

Total number of marbles N = 20

Probability (Red) = 3/20

Probability (Green) = 7/20

Probability (Blue) = 10/20

1) the probability of picking 5 marbles and getting at least one red marble

A) with replacement

P(at least 1 red of 5)= (3/20 * 17/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 17/20 * 17/20 * 17/20) + (3/20 * 3/20 * 3/20 * 17/20 * 17/20)

P(at least 1 red of 5) = 0.0783 +0.0138 + 0.0024 = 0.0945

B) without replacement

P(at least 1 red of 5) = ( 3/20 * 17/19* 16/18 * 15/17 * 14/16) + (3/20 * 2/19 * 17/18 * 16/17 * 15/16) + (3/20 * 2/19 * 1/18 * 17/17 * 16/16)

P(at least 1 red of 5) = 0.0921 + 0.01316 + 0.0009 = 0.1062

2) the probability of picking 6 marbles having 2 of each color

A) with replacement

P( 6, 2 of each) = 3/20 * 3/20 * 7/20 * 7/20 * 10/20 * 10/20

P( 6, 2 of each) = 0.0138

B) without replacement

P( 6, 2 of each) = 3/20 * 2/19 * 7/18 * 6/17 * 10/16 * 9/15

P( 6, 2 of each) = 0.00081

3) Pick 8 marbles: 4 green and 4 blue

A) with replacement

P(8, 4G and 4 B) = 7/20*7/20*7/20*7/20*10/20*10/20*10/20

P(8, 4G and 4 B) = 0.00094

B) without replacement

P(8, 4G and 4 B) = 7/20*6/19*5/18*4/17*10/16*9/15*8/14*7/13 = 0.00083

4) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

Cost of 6 .marbles= 6* 50 cents

C = 300 cents

Therefore, You will have to pay

(1 + 0.0056) 300 cent = 301.68 cents to be sure of getting at least 6 marbles of the same color

5) getting at least 6 marbles of the same color

Only Green and Blue marbles are more than 6

P(at least 6 marbles of the same color) = (7/20*6/19*5/18*4/17*3/16*2/15) + (10/20*9/19*8/18*7/17*6/16*5/15)

= 0.00018 + 0.00542

P(at least 6 marbles of the same color) = 0.0056

6 0
3 years ago
Courtney would like to buy a new ca in 4 years. It is estimated that a new car will cost her 25,000 and that she will get 13,000
KiRa [710]

4 years=48 months

A new car costs 25,000, but she will get 13,000 for her used car as long as she takes good car of it. If she takes good care of her used car and gets 13,000 for it, she will only need to save 12,000 total. We can divide 12,000 by 48 to find out how much Courtney should save minimum each month to afford her new car. 12,000/48=250

You can check to see if this is correct by multiplying 48*250=12,000. Paying 250 for each month of the 48 months will equal the $12,000 that Courtney needs.

Courtney needs to save at least $250 per month to afford her new car in 4 years.

I hope this helps :)

3 0
3 years ago
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