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NeTakaya
3 years ago
8

Equation of the line that contains the point (-9,2) and is perpendicular to the line y=-3/2x-3

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

y=2/3x+8

Step-by-step explanation:

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the coordinates of the vertex of a parabola in the xy-plane are (-4,k). If the y-intercept of the parabola is 12 and the parabol
svp [43]

The value of k is (A) 20/3.

<h3>What is a parabola?</h3>
  • A parabola is a planar curve that is mirror-symmetrical and roughly U-shaped in mathematics.
  • It fits various seemingly disparate mathematical descriptions, all of which can be shown to define the same curves.
  • A point and a line are two ways to describe a parabola.

To find the value of k:

  • y - b = c (x - a)²

Where (a, b) is the vertex and c is the constant.

  • (a, b) = (-4, k)
  • y - k = c (x - (- 4))²
  • y - k = c (x + 4)²

So,

  • x = 0, y = 12
  • 12 - k = 16c
  • k = 12 - 16c  ...... (1)

Then,

  • (-3, 7) = (x, y)
  • 7 - k = c (1)²
  • k = 7 - c  ...... (2)

Now,

  • 12 - 16c = 7 - c
  • 12 - 7 = 16c - c
  • 5 = 15c
  • c = 5/15 = 1/3

So, the value of k:

  • k = 12 - 16 (1/3) = 12 - 16/3 = 36-16/3 = 20/3

Therefore, the value of k is (A) 20/3.

Know more about a parabola here:

brainly.com/question/4061870

#SPJ4

The complete question is given below:

The coordinates of the vertex of a parabola in the XY plane are (-4,k). If the y-intercept of the parabola is 12 and the parabola passes through the point (-3,7), then what is the value of k?

(A) 20/3

(B) 16/5

(C) 14/3

(D) 12/5

5 0
1 year ago
CAN SOMEONE PLEASE HELP ME
andre [41]
70
50
60
85

Hope this helps
7 0
3 years ago
What is the distance between the points 4,10 and -3,-14 on the coordinate plane
Kryger [21]

Answer:

25

Step-by-step explanation:

Here we are supposed to find the distance between two coordinates ( 4,10) and (-3,-14).

Let us do this step by step with detailed explanation.

We will use distance formula in order to find the distance between them. The distance formula is given as

D=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} }

Here we have

x_{2}=-3\\x_{1}=4\\y_{2}=-14\\y_{1}=10\\

Replacing them in the formula we get

D=\sqrt{(-3-4)^{2} +(-14-10)^{2} }\\D=\sqrt{(-7)^{2} +(-24)^{2} }\\D=\sqrt{49+ 576 }\\D=\sqrt{625 }\\D=25\\

Hence our distance is 25 units

8 0
3 years ago
How can you solve this problem? Please help!!
polet [3.4K]
A. 13 hours
b. 0.52 hours
7 0
4 years ago
Mrs. Rivera has bars of chocolate in a box. The total mass of bars of chocolate in the box is 3 kilograms. What is the mass in g
sergeinik [125]

Answer:The chocolate in the box is 3000 grams.

Every Kilogram has 1000 grams

You multiply 1000×3=3000

6 0
3 years ago
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