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Vera_Pavlovna [14]
4 years ago
12

How can you solve this math problem 2/7y+5=9

Mathematics
2 answers:
kolbaska11 [484]4 years ago
7 0
2/7y+5=9
*it is important to note that 2 divided by 7 is the same as the fraction 2 over 7 or 2 7ths. Fractions are division.

1.) Multiple 7 by each side
2y+5=63

2.) subtract 5 from each side
2y=58

3.) divide each side by 2
y=29

4) Check your answer
2(29)+5=63
58+5=63
63=63

5.) y=29
nlexa [21]4 years ago
5 0
2/7y + 5 = 9

Subtract 5 from both sides

2/7y = 4

Multiply both sides by 7

2y = 28

Divide both sides by 2

<em><u>y = 14</u></em>
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32. The length of a rectangle measures six more than the width. The perimeter of the rectangle is 38.
Ne4ueva [31]

Answer: 12.5

You start with the equations "2x +2y=38" and "6+x=y". By adding and subtracting in the second equation, you get "2x +2y=38" and "x-y=-6". When you multiply the second equation by 2, you get "2x-2y=-12."

subtracting the equations "2x +2y=38" and "2x-2y=-12" gets you to "4y=50", where you have to divide two sides by 4 and get "y=12.5"

6 0
3 years ago
I need this answered Fast if possible. A car is traveling on a small highway and is either going 55 miles per hour or 35 miles
Alex787 [66]

a. It spends about 2.045 hours going 55 miles per hour

b. It spends 1 hour going 35 miles per hour

c. The trip would take about 3.64 hours

Step-by-step explanation:

A car is traveling on a small highway and is either going 55 miles per hour or 35 miles  per hour, depending on the speed limits, until it reaches its destination 200 miles  away

  • x represents the amount of time in hours that the car is going 55 miles per  hour
  • y represents the amount of time in hours that the car is going 35 miles per hour
  • The equation  that describing the relationship is 55x + 35y = 200

We need to find:

a. How long does it  spend going 55 miles per hour, if the car spends 2.5 hours going 35 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 2.5 hours going 35 miles per hour on the trip

∵ y represents the amount of time that the car going 35 mi./h

∴ y = 2.5

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(2.5) = 200

∴ 55x + 87.5 = 200

- Subtract 87.5 from both sides

∴ 55x = 112.5

- Divide both sides by 55

∴ x = 2.045 hours

It spends about 2.045 hours going 55 miles per hour

b.how long does it  spend going 35 miles per hour, if the car spends 3 hours going 55 miles per hour on the trip

∵ 55x + 35y = 200

∵ The car spends 3 hours going 55 miles per hour on the trip

∵ x represents the amount of time that the car going 55 mi./h

∴ x = 3

- Substitute the value of y in the equation to find the value of x

∴ 55(3) + 35y = 200

∴ 165 + 35y = 200

- Subtract 165 from both sides

∴ 35y = 35

- Divide both sides by 35

∴ y = 1 hour

It spends 1 hour going 35 miles per hour

c. How long would the trip take, if the car spends no time going 35 miles per hour

∵ 55x + 35y = 200

∵ The car spends no time going 35 miles per hour

∴ y = 0

- Substitute the value of y in the equation to find the value of x

∴ 55x + 35(0) = 200

∴ 55x  = 200

- Divide both sides by 55

∴ x = 3.63 hours

The trip would take about 3.64 hours

Learn more:

You can learn more about the equations in brainly.com/question/4097107

#LearnwithBrainly

5 0
3 years ago
I will give decent points if corrected
s2008m [1.1K]

Answer:

it's either a or b, but I would go with A

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