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Vera_Pavlovna [14]
3 years ago
12

How can you solve this math problem 2/7y+5=9

Mathematics
2 answers:
kolbaska11 [484]3 years ago
7 0
2/7y+5=9
*it is important to note that 2 divided by 7 is the same as the fraction 2 over 7 or 2 7ths. Fractions are division.

1.) Multiple 7 by each side
2y+5=63

2.) subtract 5 from each side
2y=58

3.) divide each side by 2
y=29

4) Check your answer
2(29)+5=63
58+5=63
63=63

5.) y=29
nlexa [21]3 years ago
5 0
2/7y + 5 = 9

Subtract 5 from both sides

2/7y = 4

Multiply both sides by 7

2y = 28

Divide both sides by 2

<em><u>y = 14</u></em>
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Answer:

Step-by-step explanation:

Moving back will be indicated by a negative value, forward will be positive.

- 5 + (-3) + 3 is the correct option.

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Please help me with this!!! I will mark brainliest!!
wolverine [178]

Hello from MrBillDoesMath!

Answer:

-9 sqrt(5)


Discussion:

-2 sqrt(20) -  sqrt(125) =

-2 *2 sqrt(5) - sqrt(125)=                                as 20 = 4* 5

-4sqrt(5)- 5 sqrt(5)  =                                      as 125 = 25 *5

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8 0
3 years ago
What is the equation of the following line? Be sure to scroll down first to see
Rom4ik [11]
<h2>Answer:</h2>

-1/3x

<h2>Step-by-step explanation:</h2><h3>Known :</h3>
  • x1 = -3
  • x2 = 0
  • y1 = 1
  • y2 = 0

<h3>Asked :</h3>
  • Correct line equation

<h3>Solution :</h3>

We can find the straight line equation using this formula,

\frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1}

Insert all we know inside the formula,

\frac{y-1}{0-1} = \frac{x-(-3)}{0-(-3)}\\\frac{y-1}{-1} = \frac{x +3}{3}\\

Use cross multiplication,

3(y - 1) = -1(x + 3)\

3y - 3 = -x - 3

3y = -x - 3 + 3

3y = -x

y = -1/3x

<h3>Conclusion :</h3>

The correct equation is y = -1/3x

6 0
2 years ago
Angles 1 and 5 are what type of angle pair? *
mojhsa [17]

Answer:

Angle 1 and Angle 5 are corresponding angles

Step-by-step explanation:

Two angles that lie on the same side of the transversal in corresponding positions.

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3 0
3 years ago
Read 2 more answers
Use the number line below, where RS = 8y +4, ST = 4y + 7, and RT = 107.
NISA [10]

Answer:

a) Finding value of y:

8y+4+4y+7=107

12y+11=107

12y =107-11

12y =96

y = 96/12

y = 8

b) RS= 8y+4

= 8(8)+4

= 64+4

= 68

ST= 4y+7

= 4(8)+7

= 32+7

= 39

8 0
3 years ago
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