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2 years ago

Which equation represents the following graph?

Mathematics

1 answer:

Kazeer [188]2 years ago

8 0

Answer:

y = -1/2x + 2.

Step-by-step explanation:

The slope is -2/4 = -1/2 and the y-intercept is y = 2,

so in slope-intercept form the equation is y = -1/2x + 2.

The slope is negative because the line falls to the right.

You might be interested in

Which equation could be solved using this application of the quadratic formula?

Alex_Xolod [135]

Answer:

C. x^2 + 2x - 1 = 3

Step-by-step explanation:

The standard form of a quadratic equation is

ax^2 + bx + c = 0

We need to use the quadratic formula and the given expression to find the values of a, b, and c.

The quadratic formula is

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Where the formula has -b, the problem has -2, so b = 2.

Now we have

ax^2 + 2x + c = 0

In the denominator, where the formula has 2a, the problem has 2(1), so a = 1.

Now we have

x^2 + 2x + c = 0

Inside the root, the quadratic formula has -4ac. the problem shows -4(1)(-4). Since we already know that a = 1, then c = -4.

Now we have

x^2 + 2x - 4 = 0

Let's look at choice A.

x^2 + 1 = 2x - 3

Subtract 2x from both sides. Add 3 to both sides.

x^2 - 2x + 4 = 0 This is not it!

Let's look at choice B.

x^2 - 2x - 1 = 3

Subtract 3 from both sides.

x^2 - 2x - 4 = 0 This is not it!

Let's look at choice C.

x^2 + 2x - 1 = 3

Subtract 3 from both sides.

x^2 + 2x - 4 = 0 This is it!

Answer: C. x^2 + 2x - 1 = 3

8 0

3 years ago

The loudest insect on Earth is the African cidada

igor_vitrenko [27]

Wrong subject, but that is true. You should have information to back that up also.

5 0

3 years ago

(y+6)(y - 4) = 0 0 prperty

Alex_Xolod [135]

Answer:

y = 4,-6

Step-by-step explanation:

0 property states that 0 times any number is 0

applying that here, that means y+6 = 0 or y-4 = 0

0(y-4) = 0; (y+6)(0) = 0

y+ 6 = 0

y = -6

y-4 = 0

y = 4

5 0

3 years ago

Objects A and B are in harmonic motion modeled by

Zepler [3.9K]

Answer:

The phase difference between yA and yB is $\frac{-\pi }{12}$

Step-by-step explanation:

Given harmonic modeled as :

yA = 8 sin(2t - $\frac{\pi }{3}$ ) And

yB = 8 sin(2t - $\frac{\pi }{4}$ )

The function as written as :

y = a sin(ωt - Ф) where Ф is phase difference

So , phase difference between yA and yB = ( Ф_1 - Ф_2 )

Or phase difference between yA and yB = ( - $\frac{\pi }{3}$ + $\frac{\pi }{4}$ )

Or, phase difference between yA and yB = $(\frac{-4\pi +3\pi }{12})$

I.e phase difference between yA and yB = $\frac{-\pi }{12}$

Hence The phase difference between yA and yB is $\frac{-\pi }{12}$ Answer

4 0

4 years ago

Read 2 more answers

How can i find the midpoint of a line segment ?

eimsori [14]

Answer:

add both x coordinates and divide them by 2.

add both y coordinates and divide them by 2.

Now final product should be (x,y)

Step-by-step explanation:

Example.

let's take 2 points:

(2,5) and (7, 9)

let's add both x coordinates.

2+7 = 9

now add both y coordinates.

5+9 = 14

Now divide both by 2.

Final answer should be (4.5, 7) = this is your midpoint

8 0

3 years ago