I disagree with her she will spent more than that because 6×5.29=31.74$ for 6 roses+4×3.59=14.36 4carnations +8×4.79=38.32$for 4 tulips and then 31.74+14.36+38.32=84.42$ all together
2(a+3) + 3(2a-1)
First, let's use the distributive property to expand 2(a+3):
2(a+3) = 2*a + 2*3 = 2a + 6
Let's use the distributive property now to expand 3(2a-1):
3(2a - 1) = 3*2a - 3*1 = 6a - 3
So 2(a+3) + 3(2a-1) = 2a + 6 + 6a - 3
Now you calculate variables between each others, and numbers between each others:
2a + 6 + 6a - 3 = 2a + 6a + 6 - 3 = 8a + 3
So the simplified form of 2(a+3) + 3(2a-1) is 8a + 3.
Hope this Helps! :)
There are two triangles in the figure(triangular prism) option third is correct.
<h3>What is a triangular prism?</h3>
When a triangle is, stretch it out to produce a stack of triangles, one on top of the other. A triangular prism is a name given to this novel 3D object.
The complete question is:
How many triangles are needed to draw the net of this object?
For the figure please refer to the attached picture.
As we can see in the figure we have given a triangular prism:
The triangular prism has two triangles.
A triangle for the base of the prism and a triangle for the top of the prism.
The lateral faces of the prism are rectangular.
Thus, there are two triangles in the figure(triangular prism) option third is correct.
Learn more about triangular prisms here:
brainly.com/question/16909441
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Answer:
Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.
Step-by-step explanation:
An exterior angle is an angle outside of the shape (hence ex meaning out). However, an ALTERNATE angle is an angle opposite of a transversal line of another angle. The angles on the same transversal line of 5 are 8, 7, 9, 10, 12, and 11. However, we are looking for ALTERNATE EXTERIOR angles not just exterior. 8, 7, 9, 10, and 12 are just exterior which leaves angle 11 as alternate exterior. Angle 11 is the alternate exterior of angle 5 meaning there is only 1 angle that is alternate of angle 5.