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ollegr [7]
3 years ago
14

PLEASE HELP ME !!! SOS

Mathematics
1 answer:
kramer3 years ago
8 0

Answer:6x - 2y = 22

Step-by-step explanation:

Just multiplying equation by 2

Can do it with any number

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Please help no links
posledela

.The answer to the questions are:

1. 4/15 is 0.26 but it's repeated so put a line above it

2. 22/7

3.  0.1875

4. 43/ 26

5. 0.73 again put a line above

6. 0.1875

6 0
2 years ago
in thier last game the schook football team scored an equal numbwr of points in each of the first 3 quaters then 14 in the fouth
Zarrin [17]

Answer:

they scored 10 in the first quarter

Step-by-step explanation:

44-14=30

30 divided by 3 = 10

(i got divided by 3 because its 3 quarters and i have to figure out the amount for 1 quarter)

7 0
2 years ago
An isosceles right triangle has an area 8 cm square find the length of its hypotenuse​
Ainat [17]

Answer:

5.9

Step-by-step explanation:

Area of a triangle is 1/2 base times height. the base is the horizontal part of the triangle and the height is the vertical part. Since it a isosceles they are equal. Those two segment are also called the legs (remember that for later). 4x4=16 times 1/2 equal 8 cm squared. So know me must find the hypotenuse. Since we since dealing with a right triangle we are going to use pythagorean theorem which is

{a}^{2}  +  {b}^{2} =  {c}^{2}

where a and b are the LEGS and c is the hypotenuse. the legs are also known as base and height so we use

{4}^{2}  +  {4}^{2}  =  {c}^{2}

which simplify to

16 + 16  =  {c}^{2}

32 =  {c}^{2}

\sqrt{32}

which is about 5.9

6 0
3 years ago
If H is the circumcenter of triangle BCD, find each measure. CD, CE, HD, GD, HG, HF
Levart [38]

Answer:

H is the circumcenter of triangle BCD

  • CD = 2FD = 2*32 = 64
  • CE = BE = 26
  • HD = HC = 33
  • GD = 1/2BD = 1/2(58) = 29
  • HG = √HD ²-GD² = √33²-29² = 2√62 ≈ 15.75
  • HF = √HD ²-FD² = √33²-32² =√65 ≈ 8.06
7 0
3 years ago
HELP !!!! I NEED HELP ON THIS QUESTION !!!
lord [1]
Find the volumen of the semisphere and subtract the volumes of the two cylinders

1) Volume of the semisphere:

[1/2] (4/3)π(r^3) =[ 2π(1.5m)^3 ]/3 = 7.0686 m^3

2) Volumen of the cylinders:π(r^2)h

a) π(0.75/2m)^2 (1.75m) = 0.7731 m^3

b) π(1/2m)^2 (1.25m) = 0.9818 m^3

3) 7.0686 m^3 - 0.7731 m^3 - 0.9818m^3 = 5.3137 m^3

Answer: 5.3 m^3

3 0
3 years ago
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