For each sequence, find the first 4 terms and the 10th term.
a) 12-n
B 5 - 2n
2 answers:
Answer:
Solution given:
a.
tn=12-n
1 st term =12-1=11
2nd term =12-2=10
3rd term=12-3=9
4th term=12-4=8
10th term=12-10=2
b.
tn=5-2n
1st term=5-2*1=3
2nd term=5-2*2=1
3rd term=5-2*3=-1
4th term=5-2*4=-3
10th term=5-2*10=-15
<u>(a) Solution</u>
T(n) = 12 - n
T(1) = 12 - 1 = 11
T(2) = 12 - 2 = 10
T(3) = 12 - 3 = 9
T(4) = 12 - 4 = 8
T(10) = 12 - 10 = 2
<u>(b) Solution</u>
T(n) = 5 - 2n
T(1) = 5 - 2 = 3
T(2) = 5 - 4 = 1
T(3) = 5 - 6 = -1
T(4) = 5 - 8 = -3
T(10) = 5 - 20 = -15
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