Answer: C
Step-by-step explanation:
Okay first set a comparison since the two triangles are similar
x-1/20=x-1+27/3x+8
x-1/20 = x+26/3x+8
cross multiply
20x+520=3x^2+8x-3x-8
3x^2-15x-528=0
3(x^2-5x-176)=0
im kinda lazy to factor this out so i used an online calculator right here but factor it out like a good kid
x=16, x=-11
it has to be positive so x=16
C
Think rise over run when on a graph
You find the distance of all sides to both triangle then match up the sides and see if they are similar
Answer:
Step-by-step explanation:
x^2-16y-4x-12=0
Transpose and separate x and y
16y = x^2-4x-12
16y = (x^2-4x+4) -16
16y = (x-2)^2 -16
y = (1/16)(x-2)^2 -1
This means that the vertex is at
(x-2)=0 or x=2
y = -1
=> vertex (2,-1)
