A 324-inch pipe is cut into two pieces. One piece is five times the length of the other. Find the length of the shorter piece.

salantis [7]

0.034833091436865 This is the answer. Sorry but can't show work

5 0

4 years ago

The ratio of flutes to saxophone players in the school band is 6:4 if there are 50 total students how many saxophone players are

nasty-shy [4]

There are 20 saxophone players. For every 6 flutes there are 4 saxophones so if you do 6x5=30. Then you would do 4x5 and get 20. 30 flutes plus 20 saxophones = 50 total students

3 0

3 years ago

Read 2 more answers

M<1= (2x + 7y) degrees <br> and<br> m<2= (2x+y) degrees<br> find x and y

Romashka-Z-Leto [24]

Do you have a picture for this problem? There are multiple different ways to solve this problem but I'll need a picture to help you.

3 0

3 years ago

Use the zero product property to solve the equation. (4k+5)(k+7)=0

Maru [420]

The zero product property tells us that if we have
xy=0, then we can assume that x and y both equal 0

so

(4k+5)(k+7)=0
we can assume that 4k+5=0 and k+7=0
so

4k+5=0
minus 5 both sides
4k=-5
divide both sides by 4
k=-5/4

k+7=0
minus 7 both sides
k=-7

k=-5/4 or -7

7 0

3 years ago

Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$