Answer:
t = 28.3 seconds
1200 meters
Step-by-step explanation:
The height of the rocket after t seconds from launching is given by
h(t) = - 4.9t² + 124t +416
Now, at h = 0 the rocket will splashes down.
Hence, -4.9t² + 124t + 416 = 0
Applying Sridhar Acharya formula,
t = or, t =
Hence, t = 28.3 or, t = -2.999
Since t can not be negative, so, t = 28.3 seconds. (Answer)
Now, h = -4.9t² + 124t + 416, for h to be maximum
⇒ -9.8t + 124 = 0
⇒ t =12.65 secs
Hence, meters
Therefore, the rocket peaks at 1200 meters above sea level. (Answer)