A given line has the equation 2x 12y -1.What is the equation, in slope-intercept form, of the line that is perpendicular to the
given line and passes through thepoint (0,9)?x 9SubmitSave and ExitNextMark this and return
1 answer:
First we need to arrange the given equation into slope-intercept form, as follows:
2x + 12y = -1
Subtracting 2x from both sides, we get:
12y = -2x -1 ................(1)
Next we divide both sides of equation (1) by 12, to get:
Therefore the slope in equation (2) is -(1/6)
The product of the slope of the perpendicular line and the slope of the given equation must equal -1. Let the slope of the perpendicular line be m. Then we can write:
Multiplying both sides of equation (3) by -6, results in:
m = 6
So the required number to type in the box is 6.
2x + 12y = -1
Subtracting 2x from both sides, we get:
12y = -2x -1 ................(1)
Next we divide both sides of equation (1) by 12, to get:
Therefore the slope in equation (2) is -(1/6)
The product of the slope of the perpendicular line and the slope of the given equation must equal -1. Let the slope of the perpendicular line be m. Then we can write:
Multiplying both sides of equation (3) by -6, results in:
m = 6
So the required number to type in the box is 6.
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Answer:
360,360 groups of 5 people.
Step-by-step explanation:
We have been given that there are 15 people in an office with 5 different phone lines. We are asked to find groups of 5 people that can answer these lines, if all the lines begin to ring at once.
We will use fundamental principle of counting to solve our given problem.
There are 15 people to answer 1st line, that will leave us with 14 people to answer 2nd line.
Now, we will have 13 people to answer 3rd line, that will leave us with 12 people to answer 4th line.
There are 11 people to answer 5th call.
So 5 lines can be answered in ways.
Therefore, 360,360 groups of 5 people can answer these lines.