<u>I'll assume you need to find the equation of the line that passes through those points.</u>
Answer:
Step-by-step explanation:
<u>Equation of a Line:</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
The given points are (-4,2) and (12,6), thus:
Operating:
Simplifying, the equation in point-slope form is:
640 x 0.30= 192
640-192= 448
448 is the answer
We have the same workbook lol
The answer is
Drums: 2/4
milks 4/9
(unless your teacher wants it improper.)
Answer:
145°
Step-by-step explanation:
There are a couple of ways you can get there:
1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...
... ∠BAC = 90° -∠ABC = 90° -55° = 35°
Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...
... ∠BAD = 180° -35° = 145°
2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.
... ∠BAD = 55° +90° = 145°
