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Darina [25.2K]
2 years ago
12

Helpppppppppppppp please

Mathematics
2 answers:
sashaice [31]2 years ago
8 0
You would have to list a question for me to help .
Setler [38]2 years ago
5 0

Answer:

You didn't list a question

Step-by-step explanation:

You might be interested in
What is 70/360 in percentage​
defon

Answer:

About 19.45%

Step-by-step explanation:

First set the fraction equal to x over 100 ———- (70/360)=(x/100)

cross multiply———- 70 * 100 = 7000            360 * x = 360x

solve for x —————- 7000=360x

                                   7000/360= 19.44444444

Round ——- x=19.45

OR

Divide fraction ———— 70/360 = 0.1944444444

Next, convert to percentage by moving decimal 2 places to the right ——

019.44444444

Round ————- = 19.45

3 0
3 years ago
Are these three side lengths a right triangle?<br> 5, 5, 5√s<br> yes or no?
11111nata11111 [884]

Answer:

no

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which of the following is the best buy?
-BARSIC- [3]

The $1.25 one for 9 Oz box of rice would be the best buy.

<h3>How to find the Unit Price?</h3>

To get the best buy among the given items and prices, we need to find the unit price. Thus, the formula is;

Unit price = Price/Quantity

A) Unit Price = 0.90/6 = 0.15

B) Unit Price = 1.93/12 = 0.15083

C) Unit price = 2.42/16

Unit Price = 0.15125

D) Unit Price = 1.25/9 = 0.138

The $1.25 one for 9 Oz box of rice would be the best buy.

Read more about Unit price at; brainly.com/question/2804909

#SPJ1

3 0
2 years ago
Please do the 3 questions show work if needed
pishuonlain [190]

Answer:

100-11=89

Step-by-step explanation:

6 0
3 years ago
Perform the indicated row operations, then write the new matrix.
Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]

Operations:

2R_1 + R_2 ->R_2

-3R_1 +R_3 ->R_3

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

Step-by-step explanation:

The first operation:

2R_1 + R_2 ->R_2

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by 2

2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]

\left[\begin{array}{ccc}0&5&7|1\end{array}\right]

The second operation:

-3R_1 +R_3 ->R_3

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]

Multiply by -3

-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]

Add to row 2 elements are: \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]

\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]

Hence, the new matrix is:

\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]

3 0
3 years ago
Read 2 more answers
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