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3 years ago

Never mind. I meant these problems. Please find the mean, median, and mode.

Mathematics

1 answer:

Sergio [31]3 years ago

8 0

Median mean to find the center of the data

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HELP

iris [78.8K]

Answer:

D x≥4

Step-by-step explanation:

−7 ≥ 13−5x

5x ≥ 20

x ≥ 4

6 0

2 years ago

Read 2 more answers

Find the prime factorization of 50 using exponents

Elden [556K]

Five squared with the little two and 2 because 5 Times 10 is 50 and five is prime so then from 10 and you get five and two and both five and two are prime

5 0

3 years ago

The geometric mean of 8 and 2 is<br><br> 5<br> 3<br> 4<br> 16

igomit [66]

Answer:5

Step-by-step explanation:

<h3><u>(8 + 2)</u> <u>sum of values </u> = <u>10</u> = 5</h3><h3> 2 number of values 2</h3><h3 />

There is equal spacing between the mean and the extremes

8 - 5 = 3

5 - 2 = 3

5 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago

PLEASE HELP ASAP THANK YOU

masha68 [24]

1-85.71% of the team attendance

6 0

3 years ago