Using the tree diagram what is the probability that a player will reach Level 2 with the bonus?

Stella [2.4K]

Answer:

Identity (a) can be re-written as

$sec x\ cosec x - cot x = tan x$

which we already proven in another question, while for idenity (b)

$(A)\frac 1 {sin x} -sin x = cos x \frac{cos x}{sin x}\\\\(B)\frac {1-sin^2x}{sin x} = \frac {cos^2x} {sin x} \\\\(C) \frac {cos^2x}{sin x} =\frac {cos^2x} {sin x}$

step A is simply expressing each function in terms of sine and cosine.

step B is adding the terms on the LHS while multiplying the one on RHS.

step C is replacing the term on the numerator with the equivalent from the pithagorean identity $cos^2x + sin^2x = 1$

8 0

2 years ago

Which stands for 250 feet below sea level?

Drupady [299]

-250 feet most likely is the answer

Not for sure tho but slightly sure lol

7 0

3 years ago

X ²-12x+36=0 x= ? please help fast im doing a test i will give brainleist

Luba_88 [7]

Answer x=6

(x-6)^2=0 using a^2-2ab+b^2=(a-b)^2, factor the expression

x-6=0 the only was an exponetiation can be 0 is when the base equals 0

move the constant to the right hand side and change its sign

ANSWER X=6

5 0

3 years ago

Read 2 more answers

The function f(x) = x^2 is reflected across the x-axis and a stretch factor of 4 is applied to create a second function, g(x). W

Anon25 [30]

C. The vertexes are the same. The functions' vertex (h,k) values were not altered, just a (stretch/compress).

8 0

3 years ago

Based on data collected 5 years ago, a hotel expects that 24% of all guests will request smoking rooms. The hotel suspects that

9966 [12]

Answer:

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

The hotel does not expects that 24% of all guests will request smoking rooms

Step-by-step explanation:

Step(i):-

Given the hotel takes a random sample of 223 guests. Out of this sample, 39 guests requested smoking rooms.

Sample proportion

p = x/n = 39/223 = 0.174

Given Population proportion 'P' = 0.24

Given random sample size 'n' = 223

Level of significance ∝ =0.05

The critical value Z₀.₀₅ = 1.96

Null Hypothesis (H₀) : P=0.24

Alternative Hypothesis (H₁) : P≠ 0.24

Step(ii):-

Test statistic

$Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }$

$Z = \frac{0.174-0.24}{\sqrt{\frac{0.24 X 0.76}{223} } }$

|Z| = | -2.3084|= 2.3084

The calculated value Z = 2.3084 > 1.96 at 5% level of significance

Null hypothesis is rejected

Alternative hypothesis is accepted

The hotel does not expects that 24% of all guests will request smoking rooms

7 0

3 years ago