The missing value of y such that the point (1, y) is equidistant from the points (5, 1) and (10, - 3) is - 9.125.
<h3>What is the value of the missing coordinate?</h3>
In this problem we have two points that are equisdistant to a third point, then we must solve the following Pythagorean form:
(1 - 5)² + (y - 1)² = (10 - 1)² + (- 3 - y)²
16 + (y - 1)² = 81 + (- 3 - y)²
(y - 1)² - (- 3 - y)² = 65
(y² - 2 · y + 1) - (9 + 6 · y + y²) = 65
- 8 · y - 8 = 65
y = 73 / - 8
y = - 9.125
The missing value of y such that the point (1, y) is equidistant from the points (5, 1) and (10, - 3) is - 9.125.
To learn more on equidistant points: brainly.com/question/28038252
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Answer:
Im kind of confused if I rewrite or find the y and x intercept to this equation but I hope this helps.
if you can please give me brainliest.
Answer:
14
Step-by-step:
A triangle has 3 sides, 2 of which we know and need to use in this question, i.e, 8√7 and X (which we need to solve for).
X is opposite to that 45° angle, which makes it the "opposite" and the 8√7 is the "hypotenuse"
When solving questions like this one, remember the acronym SOH CAH TOA which means: sinσ =
cosσ =
tanσ =
NB: σ= the known angle
yes because when there is a parenthesis next to a number like 5(6) it means to multiply both together just like f(x) is to multiply each other
Answer:
f(x) = (3x -2)(2x +1)
Step-by-step explanation:
The procedure for factoring expression of the form ...
ax² +bx +c
is to look for factors of a·c that have a sum of b.
The product a·c is 6·(-2) = -12. You are looking for factors that have a sum of b = -1. From your familiarity with multiplication tables, you know ...
-12 = 1(-12) = 2(-6) = 3(-4)
The sums of the factor pairs in this list are -11, -4, -1. So, the last pair of factors, {3, -4} is the one we're looking for.
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At this point, there are several ways to proceed. Perhaps the simplest is to rewrite the linear term as the sum of terms involving these factors:
-x = 3x -4x
f(x) = 6x² +3x -4x -2
Now, the expression can be factored 2 terms at a time:
f(x) = (6x² +3x) -(4x +2) . . . . . pay attention to signs
f(x) = 3x(2x +1) -2(2x +1) . . . . factor each pair
f(x) = (3x -2)(2x +1) . . . . . . . . factor out the common factor of (2x+1)