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ANTONII [103]
3 years ago
11

Which individuals in a population are the most important in determining the numbers for the Hardy-Weinberg principle since one c

an tell their genotype from their phenotype?
A. homozygous dominant
B. mutated
C. homozygous recessive
D. fittest
E. heterozygous
Biology
2 answers:
Verdich [7]3 years ago
8 0

Answer:

C. homozygous recessive

Explanation:

In a certain trait determined by one gene with two alleles, the possible genotypes and phenotypes are:

  • AA: homozygous dominant, A_ phenotype.
  • Aa: heterozygous, A_ phenotype.
  • aa: homozygous recessive, aa phenotype.

When you're given information about the amount of individuals of A_ and aa phenotypes in a population, you have no way of knowing if the individuals with the A_ phenotype are homozygous dominant or heterozygous. However, the individuals with aa phenotype have, without a doubt, homozygous recessive genotype, and you can therefore use that information to calculate the allele frequencies.

The genotypic frequencies in Hardy-Weinberg equilibrium are:

  • p²= freq (AA)
  • 2pq = freq (Aa)
  • q²=freq (aa)

And since <em>p + q = 1</em>, after calculating <em>q </em>you can obtain <em>p</em>.

AfilCa [17]3 years ago
3 0

Answer:

The answer is C: homozygous recessive

Explanation:

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