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Musya8 [376]
3 years ago
13

The 5 horses on Miranda's farm each eat 20 pounds of feed per day . How many tons of feed do the horses in in 30 days

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

1.5 tons

Step-by-step explanation:

First determine how much feed is eaten per day

5 * 20 lbs = 100 lbs per day

Then multiply by the number of days

30 * 100 = 3000 lbs

But the question asks tons, not lbs

We know there are 2000 lbs in a ton

3000lbs/ 2000lbs per ton = 1.5 tons

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Norma-Jean [14]
2 because you do what is in parenthesis first :)
3 0
3 years ago
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Write a equation of a hyperbola given the foci and the asymptotes
professor190 [17]

Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

a=3,\text{ and b=4}

To evaluate the value of h and k,

undefined

3 0
1 year ago
The mean incubation time of fertilized eggs is 19 days. Suppose the incubation times are approximately normally distributed with
pochemuha

Answer:

a)17.92

b) 16.83 .... 21.17

Step-by-step explanation:

ρ→   z

0.14 = -1.080319341

-1.080 = (x - 19)/1 = 17.92

~~~~~~~~~~~~~~~~~~

3% / 2 = 1.5%

1.5% - 98.5%

ρ→   z

0.015 = -2.170090378 ....  -2.17 = (x-19) =16.83

0.985 = 2.170090378  ....   2.17 = (x-19) =21.17

8 0
3 years ago
Solve the equation: x over 2 minus 3 equals 17
qaws [65]

Answer:

40

Step-by-step explanation:

look at the picure for step by step explanation

4 0
3 years ago
One mixture contains 6 fluid Ounces of water and 10 fluid Ounces of vinegar. A second mixture
Nadya [2.5K]

Answer:

The mixtures are not proportional.

3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture.

its =3

Step-by-step explanation:

The one mixture contains 6 fluid ounces and 10 fluid ounces of water and vinegar respectively.

Therefore, the ratio of water to vinegar in the first mixture is 6 : 10 = 3 : 5

Now, a second mixture contains 9 fluid ounces of water and 12 fluid ounces of vinegar.

Hence, the ratio of water to vinegar in the second mixture is 9 : 12 = 3 : 4

Therefore, the mixtures are not proportional.

Therefore, we have to add x fluid ounces of vinegar to the second mixture to make it in the ratio of 3 : 5.

So,

⇒ 12 + x = 15

⇒ x = 3 fluid ounces.

Therefore, 3 fluid ounces of vinegar has to be added in the second mixture to make it proportional to the first mixture. (Answer

5 0
2 years ago
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