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2 years ago

6

The speed limit on a road in Canada is 70 kilometers per hour. What is this speed in miles per hour? Round your answer to the ne

arest mile per hour.

1 answer:

Stolb23 [73]2 years ago

3 0

Answer:

The speed limit on a road in Canada is 44 miles per hour

Step-by-step explanation:

Given the speed limit on a road in Canada is 70 kilometers per hour.

We have to convert the given speed in miles per hour.

We know,

1 kilometer per hour = 0.62 miles per hours.

70 kilometer per hour = 0.621371 × 70 miles per hours.

70 kilometer per hour = 43.49597 miles per hours.

Thus, The speed limit on a road in Canada is 44 miles per hour

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In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
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$a \cdot r^2$ ,
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Second equation:

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Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

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$8\, r^2 - 25\, r + 8 = 0$ .

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Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

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