Initial cost, P = 15000
Annual depreciation, i = 0.23
Value at end of year n:
V(n)=P(1-i)^n
A. At end of year 1 (n=1)
V(1)=15000(0.77)= 11550
B. At end of year 3 (n=3)
V(3)=15000(0.77^3) = 6848.00
Answer:
Step-by-step explanation:
In the given case you would use sine
- sin = opposite / hypotenuse
- sin 47 = y/11
- y = 11 sin 47
- y = 8.0 (rounded)
Using cosine or tangent you wouldn't be able to find the value of y as the value of x is unknown