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Dovator [93]
3 years ago
14

Make A the subject of the formula R=square root of a/3

Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

R=√a/3

now put square on both side to remove square root

(√A/3)²=R²

A/3=R²

so we get

A=3(R²)

plz mark me brainest

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a car uses 9.5 L petrol per 100km a) determine the rate in km/L b) how far can the car travel with 47,5L petrol c) how many litr
Lana71 [14]

Step-by-step explanation:

a) determine the rate in km/L

==> 9.5 L/100km = 10.526316 km/L

b) how far can the car travel with 475L petrol

==> 0.210526315789473km/l

c) how many litres of petrol do they need to travel 350 km

==>Liters per km (l/km)2.86×10-3

Liters per 10 km (l/10 km)0.03

Liters per 100 km (l/100km)0.29

Kilometer per liter (km/l)350

6 0
2 years ago
HELP PLZ!!!!!!!!!!!!!!!!!!!!!
Anna35 [415]

Answer:

30

Step-by-step explanation:

9 + 13 = 22

22 + 43 = 65

65 + 55 = 120

120 ÷ 4 = 30

hope this helps

3 0
3 years ago
Can someone help me? It’s the factory one
alekssr [168]
3.21 it should be at least
3 0
3 years ago
Read 2 more answers
A rancher wishes to build a fence to enclose a 2250 square yard rectangular field. Along one side the fence is to be made of hea
Bess [88]

Answer:

The least cost of fencing for the rancher is $1200

Step-by-step explanation:

Let <em>x</em> be the width and <em>y </em>the length of the rectangular field.

Let <em>C </em>the total cost of the rectangular field.

The side made of heavy duty material of length of <em>x </em>costs 16 dollars a yard. The three sides not made of heavy duty material cost $4 per yard, their side lengths are <em>x, y, y</em>.  Thus

C=4x+4y+4y+16x\\C=20x+8y

We know that the total area of rectangular field should be 2250 square yards,

x\cdot y=2250

We can say that y=\frac{2250}{x}

Substituting into the total cost of the rectangular field, we get

C=20x+8(\frac{2250}{x})\\\\C=20x+\frac{18000}{x}

We have to figure out where the function is increasing and decreasing. Differentiating,

\frac{d}{dx}C=\frac{d}{dx}\left(20x+\frac{18000}{x}\right)\\\\C'=20-\frac{18000}{x^2}

Next, we find the critical points of the derivative

20-\frac{18000}{x^2}=0\\\\20x^2-\frac{18000}{x^2}x^2=0\cdot \:x^2\\\\20x^2-18000=0\\\\20x^2-18000+18000=0+18000\\\\20x^2=18000\\\\\frac{20x^2}{20}=\frac{18000}{20}\\\\x^2=900\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{900},\:x=-\sqrt{900}\\\\x=30,\:x=-30

Because the length is always positive the only point we take is x=30. We thus test the intervals (0, 30) and (30, \infty)

C'(20)=20-\frac{18000}{20^2} = -25 < 0\\\\C'(40)= 20-\frac{18000}{20^2} = 8.75 >0

we see that total cost function is decreasing on (0, 30) and increasing on (30, \infty). Therefore, the minimum is attained at x=30, so the minimal cost is

C(30)=20(30)+\frac{18000}{30}\\C(30)=1200

The least cost of fencing for the rancher is $1200

Here’s the diagram:

3 0
3 years ago
Please help Quickly!!
e-lub [12.9K]

Answer:

Option D 3/16

Step-by-step explanation:

Carol is cross-country skiing.

With the help of the given table we have to calculate the rate of change.

If we draw a graph for distance traveled on y-axis and tins at x-axis we find two points, ( 2, 1/6) and (3, 17/48).

Then slope of the line connecting these points will be the rate of change.

Rate of change = Slope = \frac{y-y'}{x-x'}

= \frac{\frac{17}{48}-\frac{1}{6}}{3-2}

= \frac{17-8}{48}

= \frac{9}{48}=\frac{3}{16}

Option D 3/16 is the answer.

3 0
3 years ago
Read 2 more answers
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