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3 years ago

6

The total amount of deductions for an employee's gross pay is $83.20. If the gross pay is $378.18, what percent of their gross p

ay is being withheld?

2 answers:

fredd [130]3 years ago

5 0

Answer:

22%

Step-by-step explanation:

Colt1911 [192]3 years ago

3 0

Answer:

the answer is 78 percent is being with held

Step-by-step explanation:

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What is .181818... as a fraction?

LekaFEV [45]

181818/1000000. let me know if im wrong! <3

4 0

2 years ago

How can I find a?<br> (Trigonometric Ratios)

earnstyle [38]

Step-by-step explanation:

Hey there!

<u>Use</u><u> </u><u>cos</u><u> </u><u>ratio to</u><u> </u><u>find </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>'</u><u>a'</u><u>.</u>

As per given, we can state that it is a Right angled triangle, so taking 38° reference angle.

We get;

p = AC

b = 6

and h= a

Here, <u>Use</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>b</u><u>,</u><u> </u><u>h</u><u> </u><u>and</u><u> </u><u>3</u><u>8</u><u>°</u><u> </u><u>angle</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>a</u><u>.</u>

$\cos(38° ) = \frac{b}{h}$

$\cos(38°) = \frac{6}{a}$

$0.7881 = \frac{6}{a}$ [ cos(38°=0.7881]

$0.7881a = 6$

$a = \frac{6}{0.7881}$

Therefore the measure of a is 7.61 Or 8.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

6 0

3 years ago

1.) Find the length of the arc of the graph x^4 = y^6 from x = 1 to x = 8.

xxTIMURxx [149]

First, rewrite the equation so that <em>y</em> is a function of <em>x</em> :

$x^4 = y^6 \implies \left(x^4\right)^{1/6} = \left(y^6\right)^{1/6} \implies x^{4/6} = y^{6/6} \implies y = x^{2/3}$

(If you were to plot the actual curve, you would have both $y=x^{2/3}$ and $y=-x^{2/3}$ , but one curve is a reflection of the other, so the arc length for 1 ≤ <em>x</em> ≤ 8 would be the same on both curves. It doesn't matter which "half-curve" you choose to work with.)

The arc length is then given by the definite integral,

$\displaystyle \int_1^8 \sqrt{1 + \left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx$

We have

$y = x^{2/3} \implies \dfrac{\mathrm dy}{\mathrm dx} = \dfrac23x^{-1/3} \implies \left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2 = \dfrac49x^{-2/3}$

Then in the integral,

$\displaystyle \int_1^8 \sqrt{1 + \frac49x^{-2/3}}\,\mathrm dx = \int_1^8 \sqrt{\frac49x^{-2/3}}\sqrt{\frac94x^{2/3}+1}\,\mathrm dx = \int_1^8 \frac23x^{-1/3} \sqrt{\frac94x^{2/3}+1}\,\mathrm dx$

Substitute

$u = \dfrac94x^{2/3}+1 \text{ and } \mathrm du = \dfrac{18}{12}x^{-1/3}\,\mathrm dx = \dfrac32x^{-1/3}\,\mathrm dx$

This transforms the integral to

$\displaystyle \frac49 \int_{13/4}^{10} \sqrt{u}\,\mathrm du$

and computing it is trivial:

$\displaystyle \frac49 \int_{13/4}^{10} u^{1/2} \,\mathrm du = \frac49\cdot\frac23 u^{3/2}\bigg|_{13/4}^{10} = \frac8{27} \left(10^{3/2} - \left(\frac{13}4\right)^{3/2}\right)$

We can simplify this further to

$\displaystyle \frac8{27} \left(10\sqrt{10} - \frac{13\sqrt{13}}8\right) = \boxed{\frac{80\sqrt{10}-13\sqrt{13}}{27}}$

7 0

3 years ago

Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.

Masja [62]

Answer:

See below.

Step-by-step explanation:

So, we have:

$\sec(\theta)=-2/\sqrt{3}$

Recall that secant is simply the reciprocal of cosine. So we can:

$\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2$

Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.

Therefore, the possible values for theta is

5π/6 +2nπ

and

7π/6 + 2nπ

6 0

3 years ago

ABC is an isosceles triangle in which ab and ac are equal if d is a the midpoint of BC prove that ABD=ADC

jeka94

Answer:

Step-by-step explanation:

Given that,

ABC is an Isosceles triangle.

In an Isosceles triangle the opposite sides ( AB =AC) are equal; Their base angles ( < ABD = < ACD) are also equal to each other.

It is als given that D is the mid point of BC.

i.e., BD = CD

Therefore,

By SAS theorem of congruency of triangles,

ABD = ACD

If this is the answer required, hope it helps...

4 0

3 years ago