Answer:
A = 11 i believe
Step-by-step explanation:
The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane
Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0
Answer:
I'm not sure what your looking for but I can guess numbers missing is 2 and 3?
Given that a = 2, b = 3, and c = 4.
To evaluate ab+c, we will plug given values as shown below
ab+c
=2*3+4
=6+4
=10
Hence final answer is 10.
