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aleksklad [387]
2 years ago
14

What is the average percent of time a student spend sleeping and doing homework?

Mathematics
2 answers:
Sedbober [7]2 years ago
8 0

No answer for you........

...........

leva [86]2 years ago
6 0

Answer:

41%

Step-by-step explanation:

All of those percentages need to add up to 100

8 + 8 + 13 + 13 + 25 + 33 = 100

Ok...so now that we made sure they all add up to 100, all you need to do is combine the percentage of students sleeping and doing Homework, to get the full percentage for both.

Homework = 8%

Sleeping = 33%

8 + 33 = 41

So the percent of time a student spends and doing homework is 41%.

Hope this helped!

Have a supercalifragilisticexpialidocious day!

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Answer: this is so easy you got this

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125.638 rounded to nearest hundred
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According to the picture, angles 1 and 2 have the same measure because they are corresponding angles. Make equal both expressions for 1 and 2 and find x.

\begin{gathered} 50-2x=110-42x \\ 42x-2x=110-50 \\ 40x=60 \\ x=\frac{60}{40} \\ x=\frac{3}{2} \end{gathered}

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\begin{gathered} \measuredangle1=50-2x \\ \measuredangle1=50-2(\frac{3}{2}) \\ \measuredangle1=50-3 \\ \measuredangle1=47 \\ \measuredangle2=110-42x \\ \measuredangle2=110-42(\frac{3}{2}) \\ \measuredangle2=110-63 \\ \measuredangle2=47 \end{gathered}

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The cardinality of the set B is given to be 96.

<h3>What is the cardinality of a set?</h3>

This is the term that is used to refer to the number of elements that a given set can be said to contain.

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Read more on the cardinality of a set here: brainly.com/question/23976339

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