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goldfiish [28.3K]
3 years ago
5

What is the radius of a circle with the equation (x − 3)2 + (y − 7)2 = 9? A) 3 B) 4.5 C) 6 D) 9

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ (x-\stackrel{h}{3})^2+(y-\stackrel{k}{7})^2=9\implies (x-\stackrel{h}{3})^2+(y-\stackrel{k}{7})^2=\stackrel{r}{3^2}~\hfill \begin{cases} center~(3,7)\\ radius=3 \end{cases}

Pepsi [2]3 years ago
3 0

Answer:

3

Step-by-step explanation:

(X-h)^2+ (y-k)^2=r^2

(X-6)^2+ (y+2)^2=9

R^2=9

R=3

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vovikov84 [41]

\huge\fbox{Answer ☘}

☆ given that ,

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☆ we know that ,

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Therefore ,

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therefore , ∠B = 3x = 3 ( 26° ) = 78°

\fbox{∠B \: = \: 78°}

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