1/6p - 4/5
Explanation: -2/3p needs to have the same denominator as 5/6p so they can combine. (Note, whatever sign is in front of a number determines if it is negative or positive. Your equation indicates that the bolded parts are negative and the other parts are positive: -2/3p + 1/5 - 1 + 5/6p. So what we are really doing in an equation like this is combining some numbers together)
-2/3p and 5/6p and the least common multiple of six, so we adjust the numbers to each have a denominator of 6. 5/6p is already there, so we need to adjust -2/3p.
We can multiply both the numerator and denominator by 2 to turn -2/3p into -4/6p. -4/6p has the same value as -2/3p, and now it also has the same denominator as 5/6p!
We then have to combine like terms, therefore combining -4/6p with 5/6p. When adding together fractions, the denominator does not change (this is why both numbers must have the same denominators). So our answer will be _/6p. So we combine -4 with 5, giving us one.
Therefore, -2/3p combined with 5/6p is 1/6p.
Now we have to combine our other set of like terms, 1/5 and -1. We can do this the same way that we combined the other numbers.
1/5 and -1 need the same denominator. This is simple because 1 can easily be figured out with any denominator, as long as the numerator and denominator are the same. This would make 1 = 5/5. But we need it negative, so it would be -5/5.
Now that we have common denominators, we can combine!
1/5 - 5/5
Remember what we said before, the solution will have the same denominator, so all we need to do is (in this case) subtract the numerators.
1 - 5 = 4
So that would be -4/5.
With the like terms combined, we just need to put our two combinations (1/6p and -4/5) together!
Our answer: 1/6p - 4/5
I hope that helps!
Answer:
10 milligrams
Step-by-step explanation:
Answer:
She is 11.25 years old.
Step-by-step explanation:
I just did 45 divided by 4.
Answer:
.
Step-by-step explanation:
Since repetition isn't allowed, there would be 
choices for the first donut, 
choices for the second donut, and 
choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 
unique ways to choose a bag of these donuts.
In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 
times.
For example, if a bag includes donut of type 
, 
, and 
, the count would include the following 
arrangements:
Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count by to find the actual number of donut combinations:
.
Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 
objects from a set of distinct objects:
.
Answer:
24 ounce package ( cheapest )
.
.
.
.
.
.
