Answer:
A Mutations are sometimes helpful, sometimes harmful, and sometimes neutral.
Explanation:
I did the test.
Answer:
12 : 3 : 1
Explanation:
According to Mendel's principles, a dihybrid cross between two heterozygous summer squash parents (WwGg X WwGg) should yield offsprings, 12 with white, 3 with yellow and 1 with green color phenotype. The classic Mendelian phenotypic ratio for dihybrid cross is 9:3:3:1. In this case, genotypes W- G- and W- gg produce white color phenotype. This is because we have 12: 3: 1 phenotypic ratio in which the alleles of two different genes assort independently into gametes.
<em>Dihybrid cross for heterozygous summer squash:</em>
WG Wg wG wg
WG WWGG WWGg WwGG WwGg
Wg WWGg WWgg WwGg Wwgg
wG WwGG WwGg wwGG wwGg
wg WwGg Wwgg wwGg wwgg
Genotypes:
W-G- and W- gg = white = 12
ww G- = yellow = 3
ww gg = green = 1
Answer:
E.
Explanation:
Im sorry if it's wrong but that's what I would go with
Answer:
9:3:3:1
Explanation:
This question involves two different genes coding for height and flower color respectively. The first gene posseses allele T (dominant) and t (recessive) while the second gene possesses allele P (dominant) and p (recessive).
According to this question, two heterozygous tall and purple flowers are crossed i.e. (TtPp x TtPp). Each parent will produce the following gametes combination:
TtPp - TP, Tp, tP, tp
Using these gametes in a punnet square, the following proportion of offsprings will be produced:
T_P_ (tall, purple) = 9
T_pp (tall, white) = 3
ttP_ (short, purple) = 3
ttpp (short, white) = 1
Hence, the ratio of this cross is 9:3:3:1
