Answer:
x = 31
Step-by-step explanation:
Given:
f(x) =

g(x) = x + 2
We will first find g(2).
g(2) = 2 + 2 = 4
Next we will find f(g(2)).
f(g(2))= f(4) =

Answer: (1) Distributive (2) Commutative (3) Associative
(4) Commutative (5) Addition Property of Equality
<u>Step-by-step explanation:</u>
1) Distributive
(x + 4) was multiplied by 3 and (2x - y) was multiplied by 5
2) Commutative
10x and -5y switched places
3) Associative
The parenthesis changed partners
4) Commutative
(12y - 5y) and 10x switched places
5) Addition Property
Like terms were added together --> 3x + 10x = 13x and 12y - 5y = 7y
Answer:
1) 
2) ![\sqrt[3]{-1331}=-11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D%3D-11)
3) Evaluating
we get 
4) 
5) 
Step-by-step explanation:
1) 
Prime factors of 1225 : 5x5x7x7
Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2


2) ![\sqrt[3]{-1331}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D)
We know that ![\sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B-x%7D%3D-%5Csqrt%5Bn%5D%7Bx%7D%20%5C%20%28%20%5C%20if%20%5C%20n%20%5C%20is%20%5C%20odd%29)
Applying radical rule:
![\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D%5C%5C%3D-%5Csqrt%5B3%5D%7B1331%7D%20%5C%5C%3D-%5Csqrt%5B3%5D%7B11%5Ctimes%5C11%5Ctimes11%7D%5C%5C%3D-%5Csqrt%5B3%5D%7B11%5E3%7D%20%5C%5CUsing%20%5C%20%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx%20%5C%5C%3D-11)
So, ![\sqrt[3]{-1331}=-11](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-1331%7D%3D-11)
3) 
It can be written as:

Evaluating
we get 
4) 
Put value of x, y and z in equation and solve:

So, 
5) 
We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

So, 
Answer:
sorry I can only answer no.3

Answer:
what are the equations
Step-by-step explanation:
you didnt show the equations