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trapecia [35]
3 years ago
6

TQ is equal to or congruent to QR. Find m∠SQT. A. 21 B. 10 C. 4 D. 69

Mathematics
2 answers:
Sindrei [870]3 years ago
6 0

Answer:

I know this is too late, but its 69 if you are doing a specific figure with a 90 degree angle

Step-by-step explanation:

90-21=69

Law Incorporation [45]3 years ago
3 0
D is the answer to this question.....
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QUESTION 9
Mars2501 [29]

Answer:

x = 31

Step-by-step explanation:

Given:

f(x) =

2 {x}^{2}  - 1

g(x) = x + 2

We will first find g(2).

g(2) = 2 + 2 = 4

Next we will find f(g(2)).

f(g(2))= f(4) =

2( {4}^{2} ) - 1 \\  = 2(16) - 1 \\  = 32 - 1 \\  = 31

4 0
1 year ago
Identify the property used in each of the steps​
suter [353]

Answer: (1) Distributive (2) Commutative (3) Associative

              (4) Commutative  (5) Addition Property of Equality

<u>Step-by-step explanation:</u>

1) Distributive

(x + 4) was multiplied by 3 and (2x - y) was multiplied by 5

2) Commutative

10x and -5y switched places

3) Associative

The parenthesis changed partners

4) Commutative

(12y - 5y) and 10x switched places

5) Addition Property

Like terms were added together --> 3x + 10x = 13x and 12y - 5y = 7y

5 0
3 years ago
Evaluate the following pic
GREYUIT [131]

Answer:

1) \sqrt{1225}+\sqrt{1024}=67

2)  \sqrt[3]{-1331}=-11

3) Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

Step-by-step explanation:

1) \sqrt{1225}+\sqrt{1024}

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67

\sqrt{1225}+\sqrt{1024}=67

2) \sqrt[3]{-1331}

We know that \sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)

Applying radical rule:

\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11

So, \sqrt[3]{-1331}=-11

3) 2:p :: p:8

It can be written as:

p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4

Evaluating 2:p :: p:8 we get p=\pm 4

4) x^3+y^2+z \ when \ x=3, y=-2, x=-6

Put value of x, y and z in equation and solve:

x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25

So, x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}

5) \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6

So, \frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6

8 0
2 years ago
HELP I WILL GIVE BRAINIEST
Sholpan [36]

Answer:

sorry I can only answer no.3

4x - 2 = 180 \\ 4x = 180  + 2 \\ 4x + 3x = 182 \\  \frac{7x}{7}  =  \frac{182}{7}  \\ x = 26

7 0
3 years ago
Which of the following equations could represebt the point in the table select all the following
r-ruslan [8.4K]

Answer:

what are the equations

Step-by-step explanation:

you didnt show the equations

6 0
2 years ago
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