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Crazy boy [7]
3 years ago
7

Write the following inequality using interval notation

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
I think the answer is (9,8)
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Write an equation of the circle with center (3, -6) and radius 5.
lesya692 [45]

Answer:

formula for a circle: (x-h)^2 + (y-k)^2 = r^2, where (h,k) is the center and r is the radius.

1. Plug in center coordinates into formula

(x-3)^2 + (y-(-6))^2 = r^2

2. Plug in radius value

(x-3)^2 + (y-(-6))^2 = 5^2

3. Simplify:

(x-3)^2 + (y+6)^2 = 25

3 0
4 years ago
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Please help with the problem below
Andrej [43]

Answer:

ow that so hard

Step-by-step explanation:

wait let me see the answer i well search it

5 0
3 years ago
Consider the equation: x^2 = - 8x - 7​
Airida [17]

Answer: The expression is not factorable with rational numbers.

Step-by-step explanation:

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3 years ago
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Find the value of x and simplify completely.
jok3333 [9.3K]

Answer:

<h2>x=9√10</h2>

Given: A right triangle in which an altitude is drawn from the right angle vertex to the hypotenuse.

To find: 'x' the larger leg of triangle

Solution,

Using let rule for similarity in right triangle:

\frac{leg}{part}  =  \frac{hypotenuse}{leg}  \\ or \:  \frac{x}{27}  =  \frac{3 + 27}{x}  \\ or \: x \times x = 27(3 + 27) \\ or \: x \times x = 81 + 729 \\ or \:  {x}^{2}  = 810 \\ or \:  {x}^{2}  = 81 \times 10 \\ or \:  {x}  =  \sqrt{81 \times 10}  \\ or \: x =  \sqrt{81}  \times  \sqrt{10}  \\ or \: x =  \sqrt{ {(9)}^{2} }  \times  \sqrt{10}  \\  \: x = 9 \sqrt{10}

Hope this helps...

Good luck on your assignment..

7 0
3 years ago
Rewrite the expression in z to the n power. The expression I was given is: 1 over z to the negative 1 half power.
12345 [234]

Answer:

The equivalent expression is;

\frac{1}{z^{-\frac{1}{2}}}=z^{\frac{1}{2}}

Step-by-step explanation:

The given expression is:


\frac{1}{z^{-\frac{1}{2} }}

Recall that:

\frac{1}{a^{-m}}=a^m


In our case, a=z and  m=\frac{1}{2}.


We use this property of exponent to obtain;

\frac{1}{z^{-\frac{1}{2}}}=z^{\frac{1}{2}}


6 0
3 years ago
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