Determining a car's depreciation over a ten year period is considered a bivariate.
<h3>What is a bivariate?</h3>
A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.
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The answer to the question would be 455
You would input 10 as m into the equation
t= 0.05(10) +60
t=0.5+60
t=60.5
Well the probability of rolling a six on it would be 1/20.
So, if you're rolling it 1,000 times, 1,000 x 1/20 = 50.
You would roll a six approximately 50 times.
Amount borrowed, P = 13000
Interest, i = 0.07/12 per month
number of periods (months), n = 4*12 = 48
Monthly payment,


=
311.30 (to the nearest cent)