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3 years ago

Which point is a solution to the inequality shown in this graph

Mathematics

2 answers:

astra-53 [7]3 years ago

8 0

Answer:

D: (1,5) Apex

Step-by-step explanation:

Stels [109]3 years ago

8 0

Answer:

Option D. (1, 5)

Step-by-step explanation:

An inequality has been graphed in the given question.

The shaded part upwards the dotted line shows that the solution of the inequality lies in this region.

Now we will consider those points of the options as a solution which lie in the shaded region.

Option A.(3, -1)

Since line is in dotted form therefore points lying on the line are not the solution.

Option B. (5, -5)

Since this point lie below the shaded region so it's not the solution.

Option C. (-3, -3)

This point is again on the dotted line so it's not the solution.

Option D. (1, 5)

This is the correct option because this point lies in the shaded region above the dotted line.

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Given uv = su tu sv prove vt = st

Lady bird [3.3K]

Answer: see proof below

<u>Step-by-step explanation:</u>

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3 years ago

V=πr^2h/3 solve for h

Aneli [31]

Answer:

h = 3V / πr^2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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3 years ago

Write 9/10 as an equivalent fraction with a denominator of 100 then write the fraction as a decimal

Firlakuza [10]

Answer:

Since the denominator has to be 100 and 9/10, 0.90, and 90% are all equal the you would just need to make the 9 into a 90. Therefore, yout answer will be 90/100.

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2 years ago

Yo can someone help me with this please and please ex plain

Novay_Z [31]

Answer:

c) The car dealer's business is expanding rapidly.

Step-by-step explanation:

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2 years ago

Triangle RST has vertices located at R (2, 3), S (4, 4), and T (5, 0).

LiRa [457]

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

<h3>Linear equation</h3>

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

For RS:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(4-3)^2+(4-2)^2}=2.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{4-3}{4-2}=0.5$

For RT:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-3)^2+(5-2)^2}=4.24 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-3}{5-2}=-1$

For ST:

$Length = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}=\sqrt{(0-4)^2+(5-4)^2}=4.12 \\
\\
slope=\frac{y_2-y_1}{x_2-x_1} =\frac{0-4}{5-4}=-4$

The length of the sides are 2.24, 4.24 and 4.12 units while the slope are 0.5, -1 and -4.

Find out more on linear equation at: brainly.com/question/14323743

5 0

2 years ago