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ElenaW [278]
2 years ago
13

∠A = ___∘ Round your answer to the nearest hundredth.

Mathematics
2 answers:
larisa86 [58]2 years ago
6 0

Answer: 45.58 degrees

Step-by-step explanation:

\sin A=5/7\\A=sin^{-1}(5/7) \approx 45.58^{\circ}

Firlakuza [10]2 years ago
6 0
Use Inverse tan (tan-1)
Tan-1(5/7) = 35.54 degrees
Angle A = 35.54°
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The two square pyramids are similar. The side length of the smaller pyramid is 3/4 the side length of the larger pyramid.
Triss [41]

Answer:9/16

Step-by-step explanation:

Since we know it's 3/4 use

r=(3/4)²  .... (\frac{3}{4} x\frac{3}{4} ) =\frac{9}{16}

3 0
3 years ago
PLEASE HELP
gayaneshka [121]
Area would be 66

You would simply multiple the width be the height to get your area!
5 0
3 years ago
(PICTURE) Can someone please help me out Im reporting trolls. Marking brainliest
Goshia [24]

Answer:

smart dot company would be c=.50t+12

communication plus would be c=2.50t

Step-by-step explanation:

smart dot starts with $12 a month and adds $0.50 for each hour of internet use. communication plus has no starting fee so it just adds $2.50 for each hour of internet use.

So then for the table you would put the number given for time in for the letter t and find what c would be. This would then find your cost for that amount of hours. To get you started smart dot company starts off with 0 hours so put that in for t being c=0.50(0)+12 and c=12. Communication plus also starts with 0 so it would be c=2.50(0) and c=0

Then you graph once you have both values you can graph having x=time and y=cost

Let me know if this helps!

4 0
3 years ago
Which is bigger negative 4 or negative 5
VladimirAG [237]
The answer would be - 4, since as negative numbers move away from zero, their value will get smaller and smaller as opposed to positive numbers which gets bigger and bigger as it moves away from zero.
6 0
3 years ago
Read 2 more answers
Prove that 1/sin^2A -1/tan^2A= 1
Vika [28.1K]

Answer:

Step-by-step explanation:

LHS =\dfrac{1}{Sin^{2} \ A }-\dfrac{1}{Tan^{2} \ A }\\\\\\ = \dfrac{1}{sin^{2} \ A}- \dfrac{1}{\dfrac{Sin^{2} \ A}{Cos^{2} \ A}}\\\\\\= \dfrac{1}{sin^{2} \ A } - \dfrac{Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{1-Cos^{2} \ A}{Sin^{2} \ A}\\\\\\= \dfrac{Sin^{2} \ A}{Sin^{2} \ A}\\\\\\= 1 = \ RHS

Hint: 1 - Cos² A = Sin² A

4 0
3 years ago
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