I really need help I need to estimate using benchmarks of 25 The equation is 12.54 +7.98
1 answer:
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Answer:
(6.931, 7.5)
Step-by-step explanation:
The point of maximum growth of a logistic function is always halfway between the horizontal asymptotes. Here, those are y=0 and y=15, so the point of interest is where f(x) = 15/2:
15/2 = 15/(1+4e^(-.2x)) . . . . . use 15/2 for f(x)
2 = 1 +4e^(-.2x) . . . . . . . . . . . match denominators
1/4 = e^(-.2x) . . . . . . . . . . . . . subtract 1, divide by 4
ln(1/4)/-0.2 = 5·ln(4) = x ≈ 6.93147 . . . . . . take natural logs, evaluate
The ordered pair (x, f(x)) is (6.93147, 7.5).
